joz*_*ozi 8 sql for-xml sql-server-2008
我们有一个简单的表,需要转换为XML
Declare @Person TABLE
( [BusinessEntityID] [int] NOT NULL,
[PersonType] [varchar](2) NULL,
[Title] [varchar](30) NULL,
[FirstName] [varchar](30) NULL,
[MiddleName] [varchar](30) NULL,
[LastName] [varchar](30) NULL)
Insert Into @Person Values(10001,'IN','Article','Carolyn','Jo','Alonso')
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我们需要这个xml用于在sql server中使用For XML输出
<?xml-stylesheet type='text/xsl' href='result.xsl'?>
<documents>
<document>
<field name="BusinessEntityID">10001</field>
<field name="PersonType">IN</field>
<field name="Title">Article</field>
<field name="FirstName">Carolyn</field>
<field name="MiddleName">Jo</field>
<field name="LastName">Alonso</field>
</document>
</documents>
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小智 8
以下XML PATH查询应该可以帮助您完成大部分工作.您只需添加样式表标题即可.
SELECT
'BusinessEntityID' AS 'document/field/@name'
, BusinessEntityID AS 'document/field'
, '' AS 'document'
, 'documentType' AS 'document/field/@name'
, PersonType AS 'document/field'
, '' AS 'document'
, 'Title' AS 'document/field/@name'
, Title AS 'document/field'
, '' AS 'document'
, 'FirstName' AS 'document/field/@name'
, FirstName AS 'document/field'
, '' AS 'document'
, 'MiddleName' AS 'document/field/@name'
, MiddleName AS 'document/field'
, '' AS 'document'
, 'LastName' AS 'document/field/@name'
, LastName AS 'document/field'
, '' AS 'document'
FROM @Person
FOR XML PATH(''), ROOT('documents')
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