如何显示数组中数组值的时间？

Question

我有一个包含重复值的数组.我需要显示在数组中找到每个值的次数.

让我们说我有一个包含8个值的数组,array = {1,2,3,1,1,2,6,7}我需要输出为:

1 was found 3 times
2 was found 2 times
3 was found 1 time
6 was found 1 time
7 was found 1 time

这是我的代码.现在我将数组中的每个值保存到变量,然后循环遍历数组以检查值是否存在然后将其打印出来.

 int[] nums = { 2, 4, 14, 17, 45, 48, 5, 6, 16, 25, 28, 33, 17, 26, 35, 44, 46, 49, 5, 6, 20, 27, 36, 45, 6, 22, 23, 24, 33, 39, 4, 6, 11, 14, 15, 38, 5, 20, 22, 26, 29, 47, 7, 14, 16, 24, 31, 32 };
            for (int i = 0; i < nums.Length; i++)
            {
                int s = nums[i];
                for (int j = 0; j < nums.Length; j++)
                {
                    if (s == nums[j])
                    {
                        Console.WriteLine(s);
                    }
                }

            }

提前致谢

Answer 1

foreach(var grp in nums.GroupBy(x => x).OrderBy(grp => grp.Key)) {
    Console.WriteLine("{0} was found {1} times", grp.Key, grp.Count());
}

的GroupBy(通过使用本身作为键的号码将所有的值成组x => x).对于每个唯一值,我们将拥有一个不同的组,其中包含一个或多个值.将OrderBy确保我们(通过报告在关键阶组grp => grp.Key).最后,Count告诉我们识别出的组中有多少项Key(原始值,如果您还记得).