如何使用sed用shell变量替换文件中的字符串

Question

Geez,我试过MAN页面,这里有几个帖子.我想我只是愚蠢因为我',而不是得到它.

我有一个javascript文件,其中包含{VERSION}和{DISTRO},其中变量字符串值应该像这样替换.

var MyObject = {

    /**
     * @property {string} VERSION Holds the current version of the framework
     */
    VERSION:    '{VERSION}',
    /**
     * @property {string} DISTRO Holds the distrobution tag of the framework
     */
    DISTRO:     '{DISTRO}'
};

这个命令运行我的shell.无论我做什么,它都不起作用或我得到错误.

VERSION="0.9.0"
DISTRO="Developer"
OUT_CAT=$OUT_CAT_DEBUG


${OUT_CAT} | sed -i "s/{VERSION}/\$VERSION/" -e "s/{DISTRO}/\$DISTRO/" ${OUT_CAT}
#sed -i "s/{VERSION}/$VERSION/" -e "s/{DISTRO}/$DISTRO/" ${OUT_CAT}

那么我在哪个方面？看起来它应该非常简单直接.

[编辑]这是脚本的三脚版,这样你就可以告诉我在做什么以及变量来自哪里.

#!/bin/bash
VERSION="0.9.0"

DEV_DIR=../lib
DIST_DIR=../dist
WEB_DIR=/d/Android_Dev/GitHUB/WEB/h5c3/dist

OUT_CAT_DEBUG=h5c3.debug.cat
OUT_MIN_DEBUG=h5c3.debug.min
OUT_ZIP_DEBUG=$DIST_DIR/h5c3.debug.gz

OUT_CAT_RELEASE=$DIST_DIR/h5c3.release.cat
OUT_MIN_RELEASE=h5c3.release.min
OUT_ZIP_RELEASE=$DIST_DIR/h5c3.release.gz

echo Building Version "$1"...

if [ "$1" == debug ]; then
    DISTRO="Developer"
    OUT_CAT=$OUT_CAT_DEBUG
    OUT_MIN=$OUT_MIN_DEBUG
    OUT_ZIP=$OUT_ZIP_DEBUG
    # empty it out
    > ${OUT_CAT}
    cat $DEV_DIR/packed.js >> ${OUT_CAT}
    #Development support
    cat $DEV_DIR/h5c3_debug.js >> ${OUT_CAT}
elif [ "$1" == release ]; then
    DISTRO="Production"
    OUT_CAT=$OUT_CAT_RELEASE
    OUT_MIN=$OUT_MIN_RELEASE
    OUT_ZIP=$OUT_ZIP_RELEASE
    # empty it out
    > ${OUT_CAT}
    cat $DEV_DIR/packed.js >> ${OUT_CAT}
    cat $DEV_DIR/h5c3_release.js >> ${OUT_CAT}
else
    #publish.sh debug
    #publish.sh release
    exit 2
fi

#Build Game Core
cat $DEV_DIR/core/stacktrace.js >> ${OUT_CAT}

#Build Externals
cat $DEV_DIR/ext/base64.js >> ${OUT_CAT}

#Build Engine
cat $DEV_DIR/engine/boot.js >> ${OUT_CAT} 

#Build Internal Components
cat $DEV_DIR/components/component.js >> ${OUT_CAT}

#Build Systems
cat $DEV_DIR/systems/system.js >> ${OUT_CAT}

#Build Framework
cat $DEV_DIR/framework/page.js >> ${OUT_CAT} 

#Build Web App
cat $DEV_DIR/webapp/game.js >> ${OUT_CAT}

if [ "$1" == debug ]; then
    #Development support
    cat $DEV_DIR/debugger/profiler.js >> ${OUT_CAT}
    cat $DEV_DIR/debugger/console.js >> ${OUT_CAT}
    cat $DEV_DIR/debugger/debug.js >> ${OUT_CAT}
    cat $DEV_DIR/debugger/developer.js >> ${OUT_CAT}
fi

if [ "$1" == release ]; then
    echo Removing any debug calls from ${OUT_CAT}
    sed -i '/this.debug/d' ${OUT_CAT}
fi

echo "Inserting distribution & version in ${OUT_CAT}"
${OUT_CAT} | sed -i "s/{VERSION}/\$VERSION/" -e "s/{DISTRO}/\$DISTRO/" ${OUT_CAT}

echo Minimizing...[${OUT_CAT} to ${OUT_MIN}]
> ${OUT_MIN}
java -jar yuicompressor-2.4.7.jar ${OUT_CAT} -o ${OUT_MIN}

#echo Compressing...[${OUT_MIN} to ${OUT_ZIP}]
#gzip --best --force ${OUT_MIN}

echo Copying to WEB Folder...
cp --update ${OUT_MIN} ${WEB_DIR}

echo Complete.
exit

Answer 1

看起来你正在尝试将sed和使用文件组合在一起.以下将完美无缺,

sed -i -e "s/{VERSION}/${VERSION}/" -e "s/{DISTRO}/${DISTRO}/" ${OUT_CAT}

您不需要转义$,sed因为您正在使用-i来就地修改文件,所以您不需要进行管道传输.-e当每个表达式不止一个时,您还需要使用它们.

编辑:这是sed手册页中的位,用于指示问题的-e选项(强调我的),

如果没有给出-e, - expression,-f或--file选项,则将第一个非选项参数作为要解释的sed脚本.所有剩余的参数都是输入文件的名称 ; 如果未指定输入文件,则读取标准输入.