doctrine2 findby两列OR条件

cra*_*ter 5 symfony doctrine-orm symfony-2.1

我的行动:

   $matches_request = $em->getRepository('Bundle:ChanceMatch')->findByRequestUser(1);
   $matches_reply = $em->getRepository('Bundle:ChanceMatch')->findByReplyUser(1);
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是否可以or使用getRepository 加入查询条件,例如.

$matches_reply = $em->getRepository('FrontendChancesBundle:ChanceMatch')->findBy(array('requestUser' => 1, 'replyUser' => 1); 
//this of course gives me the a result when `requestUser` and `replyUser` is `1`. 
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我的桌子

id | requestUser | replyUser
....
12 |      1      |     2
13 |      5      |     1
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我的查询应该返回id 12 & 13.

感谢帮助!

tom*_*rke 12

您可以使用QueryBuilder或为该实体创建自定义存储库,并创建一个内部使用QueryBuilder的函数.

$qb = $em->getRepository('FrontendChancesBundle:ChanceMatch')->createQueryBuilder('cm');
$qb
    ->select('cm')
    ->where($qb->expr()->orX(
        $qb->expr()->eq('cm.requestUser', ':requestUser'),
        $qb->expr()->eq('cm.replyUser', ':replyUser')
    ))
    ->setParameter('requestUser', $requestUserId)
    ->setParameter('replyUser', $replyUserId)
;
$matches_reply = $qb->getQuery()->getSingleResult();
// $matches_reply = $qb->getQuery()->getResult(); // use this if there can be more than one result
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有关自定义存储库的更多信息,请参阅官方文档:

http://symfony.com/doc/2.0/book/doctrine.html#custom-repository-classes