我的任务是创建一个返回以下数据的查询:
[架构名称],[对象名称],[扩展属性名称],[扩展属性值]
任何想法如何实现这一目标?我找到了fn_listextendedproperty函数,但这没有多大帮助.
Joe*_*uff 22
使用特定于列的查询:
SELECT S.name as [Schema Name], O.name AS [Object Name], ep.name, ep.value AS [Extended property]
FROM sys.extended_properties EP
INNER JOIN sys.all_objects O ON ep.major_id = O.object_id
INNER JOIN sys.schemas S on O.schema_id = S.schema_id
INNER JOIN sys.columns AS c ON ep.major_id = c.object_id AND ep.minor_id = c.column_id
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将此查询用于所有扩展的属性:
SELECT S.name as [Schema Name], O.name AS [Object Name], ep.name, ep.value AS [Extended property]
FROM sys.extended_properties EP
LEFT JOIN sys.all_objects O ON ep.major_id = O.object_id
LEFT JOIN sys.schemas S on O.schema_id = S.schema_id
LEFT JOIN sys.columns AS c ON ep.major_id = c.object_id AND ep.minor_id = c.column_id
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