测试自定义验证angularjs指令

Question

此自定义验证指令是官方角度站点上提供的示例. http://docs.angularjs.org/guide/forms 它检查文本输入是否为数字格式.

var INTEGER_REGEXP = /^\-?\d*$/;
app.directive('integer', function() {
  return {
    require: 'ngModel',
    link: function(scope, elm, attrs, ctrl) {
      ctrl.$parsers.unshift(function(viewValue) {
        if (INTEGER_REGEXP.test(viewValue)) {
          // it is valid
          ctrl.$setValidity('integer', true);
          return viewValue;
        } else {
          // it is invalid, return undefined (no model update)
          ctrl.$setValidity('integer', false);
          return undefined;
        }
      });
    }
  };
});

为了对这段代码进行单元测试,我写道:

describe('directives', function() {
  beforeEach(module('exampleDirective'));

  describe('integer', function() {
    it('should validate an integer', function() {
      inject(function($compile, $rootScope) {
        var element = angular.element(
          '<form name="form">' +
            '<input ng-model="someNum" name="someNum" integer>' +
          '</form>'
          );
        $compile(element)($rootScope);
        $rootScope.$digest();
        element.find('input').val(5);
        expect($rootScope.someNum).toEqual(5);
      });
    });
  });
});

然后我收到这个错误:

Expected undefined to equal 5.
Error: Expected undefined to equal 5.

我把print语句放在任何地方,看看发生了什么,看起来这个指令永远不会被调用.测试像这样的简单指令的正确方法是什么？

Answer 1

其他答案的测试应写成:

describe('directives', function() {
  var $scope, form;
  beforeEach(module('exampleDirective'));
  beforeEach(inject(function($compile, $rootScope) {
    $scope = $rootScope;
    var element = angular.element(
      '<form name="form">' +
      '<input ng-model="model.somenum" name="somenum" integer />' +
      '</form>'
    );
    $scope.model = { somenum: null }
    $compile(element)($scope);
    form = $scope.form;
  }));

  describe('integer', function() {
    it('should pass with integer', function() {
      form.somenum.$setViewValue('3');
      $scope.$digest();
      expect($scope.model.somenum).toEqual('3');
      expect(form.somenum.$valid).toBe(true);
    });
    it('should not pass with string', function() {
      form.somenum.$setViewValue('a');
      $scope.$digest();
      expect($scope.model.somenum).toBeUndefined();
      expect(form.somenum.$valid).toBe(false);
    });
  });
});

请注意,$scope.$digest()现在调用后$setViewValue.这将表单设置为"脏"状态,否则它将保持"原始"状态,这可能不是您想要的.

Answer 2

我通过读取角度应用程序代码来解决 这个问题https://github.com/angular-app/angular-app这个视频也有帮助http://youtu.be/ZhfUv0spHCY?t=31m17s

我犯的两个错误:

• 在进行ng-model时,不要直接绑定到范围
• 使用表单控制器直接操作指令传递的内容

这是更新版本.该指令是相同的,只是我改变的测试.

describe('directives', function() {
  var $scope, form;
  beforeEach(module('exampleDirective'));
  beforeEach(inject(function($compile, $rootScope) {
    $scope = $rootScope;
    var element = angular.element(
      '<form name="form">' +
        '<input ng-model="model.somenum" name="somenum" integer />' +
      '</form>'
    );
    $scope.model = { somenum: null }
    $compile(element)($scope);
    $scope.$digest();
    form = $scope.form;
  }));

  describe('integer', function() {
    it('should pass with integer', function() {
      form.somenum.$setViewValue('3');
      expect($scope.model.somenum).toEqual('3');
      expect(form.somenum.$valid).toBe(true);
    });
    it('should not pass with string', function() {
      form.somenum.$setViewValue('a');
      expect($scope.model.somenum).toBeUndefined();
      expect(form.somenum.$valid).toBe(false);
    });
  });
});