C#'get'访问者无法识别

use*_*261 6 c# xna get accessor

http://xbox.create.msdn.com/en-US/education/tutorial/2dgame/creating_the_player,它被指示使用此代码:

public int Width()
    {
        get { return PlayerTexture.Width; }
    }

    public int Height()
    {
        get { return PlayerTexture.Height; }
    }
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但是,"get"访问器似乎根本不被识别.我收到以下错误:

  • 当前上下文中不存在名称"get".

  • 只有赋值,调用,递增,递减和新对象表达式才能用作语句.

我错过了'使用系统.(某事)'线路吗?我在调查我的问题时已经成功地使用过无数次,但我找不到任何碰到同样事情的人.

我正在使用XNA Game Studio 4.0和Microsoft Visual C#2010 Express.这是我的Player.cs类的完整代码:

using System;
using Microsoft.Xna.Framework;
using Microsoft.Xna.Framework.Graphics;

namespace Shooter
{
class Player
{
    private Texture2D PlayerTexture;
    public Vector2 Position;
    public bool Active;
    public int Health;

    public int Width()
    {
        get { return PlayerTexture.Width; }
    }

    public int Height()
    {
        get { return PlayerTexture.Height; }
    }

    public void Initialise(Texture2D texture, Vector2 position)
    {
        PlayerTexture = texture;
        Position = position;
        Active = true;
        Health = 100;
    }

    public void Update()
    {
    }

    public void Draw(SpriteBatch spriteBatch)
    {
        spriteBatch.Draw(PlayerTexture, Position, null, Color.White, 0f, Vector2.Zero, 1f, SpriteEffects.None, 0f);
    }
}
}
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Jon*_*eet 15

这不是有效的属性声明:

public int Width()
{
    get { return PlayerTexture.Width; }
}
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()部分不正确 - 看起来您正在尝试声明方法而不是属性.你应该有:

public int Width
{
    get { return PlayerTexture.Width; }
}
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(我没有检查其余部分,但这可能就是错误.)

  • 乔恩,我对这种回答速度感到敬畏! (2认同)