Her*_*nan 7 c# linq reflection lambda
我找不到从Expression <Func <T1,bool >>转换为Expression <Func <T2,bool >>的方法.因为我使用了大量的反射,实际上,我真正需要的是一种采用类型参数并执行转换的方法.
public object Convert(Expression<Func<T1,bool>> expr, Type t);
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T2来自T1
public class T1 {
int FamilyId {get; set;}
}
public class T2 : T1 {
... other properties
}
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我在基类上定义了一个过滤器表达式
Expression<Func<T1,bool>> filter = p => p.FamilyId == [some value]
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我想申请List <T2>
Tim*_*lds 10
这是你在找什么?该方法有两种形式:第一种允许您将新输入类型作为参数传递; 第二个允许您将输入类型作为泛型参数传递,并获得强类型的LambdaExpression.
public static LambdaExpression ChangeInputType<T, TResult>(Expression<Func<T, TResult>> expression, Type newInputType)
{
if (!typeof(T).IsAssignableFrom(newInputType))
throw new Exception(string.Format("{0} is not assignable from {1}.", typeof(T), newInputType));
var beforeParameter = expression.Parameters.Single();
var afterParameter = Expression.Parameter(newInputType, beforeParameter.Name);
var visitor = new SubstitutionExpressionVisitor(beforeParameter, afterParameter);
return Expression.Lambda(visitor.Visit(expression.Body), afterParameter);
}
public static Expression<Func<T2, TResult>> ChangeInputType<T1, T2, TResult>(Expression<Func<T1, TResult>> expression)
{
if (!typeof(T1).IsAssignableFrom(typeof(T2)))
throw new Exception(string.Format("{0} is not assignable from {1}.", typeof(T1), typeof(T2)));
var beforeParameter = expression.Parameters.Single();
var afterParameter = Expression.Parameter(typeof(T2), beforeParameter.Name);
var visitor = new SubstitutionExpressionVisitor(beforeParameter, afterParameter);
return Expression.Lambda<Func<T2, TResult>>(visitor.Visit(expression.Body), afterParameter);
}
public class SubstitutionExpressionVisitor : ExpressionVisitor
{
private Expression before, after;
public SubstitutionExpressionVisitor(Expression before, Expression after)
{
this.before = before;
this.after = after;
}
public override Expression Visit(Expression node)
{
return node == before ? after : base.Visit(node);
}
}
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