Mac*_*ato -1 mysql sql select row
我有一张桌子:
细节
--------------------------------------------------------
ID | PARENT_ID | DATA_KEY | DATA_VALUE
========================================================
1 | 1 | Guitar | 4
--------------------------------------------------------
2 | 1 | Radio | 2
--------------------------------------------------------
3 | 1 | Tv | 2
--------------------------------------------------------
4 | 1 | Drum Kit | 3
--------------------------------------------------------
5 | 2 | Guitar | 4
--------------------------------------------------------
6 | 2 | Radio | 2
--------------------------------------------------------
7 | 2 | Tv | 2
--------------------------------------------------------
8 | 2 | Drum Kit | 3
--------------------------------------------------------
9 | 3 | Guitar | 1
--------------------------------------------------------
10 | 3 | Radio | 2
--------------------------------------------------------
11 | 3 | Tv | 2
--------------------------------------------------------
12 | 3 | Drum Kit | 3
--------------------------------------------------------
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我如何在 mysql 中选择满足以下条件的不同 PARENT_ID:
查询的预期输出应该是
-------------
PARENT_ID
=============
1
-------------
2
-------------
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由于只有 PARENT_ID 1 和 2 具有 'Guitar' = '4' 和 'Radio' = '2'
SELECT DISTINCT a.parent_id
FROM details AS a
JOIN details AS b ON a.parent_id=b.parent_id
WHERE a.data_key='Guitar' AND a.data_value='4' AND
b.data_key='Radio' AND b.data_value='2';
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