OpenCV:使用ORB比较多个图像

Question

我正在尝试创建一个C++程序,与一个输入图像相比,列表中有很多图像.我得到了整个工作,程序正在创建DMatch匹配.

现在我试图确定与源图像进行比较的图像列表中哪一个是最佳匹配.我首先尝试通过比较图像之间的匹配数来做到这一点,但问题是当生成的图像有很多关键点时; 他们也往往有很多比赛,至少在我的计划中.

那么如何确定哪个图像阵列与源图像最匹配？我正在使用此循环来确定匹配但它并不真正起作用:

vector< vector<DMatch> > filteredMatches;
vector<int> goodIds;
Ptr<DescriptorMatcher> matcher(new BFMatcher(NORM_HAMMING, false));

printf("bad matches: ");

for(size_t i = 0; i < images.size();i++){
    vector<DMatch> matches, good_matches;

    matcher->clear();
    matcher->match(images[i], tex_des, matches);
    if(matches.size() < 8){
        printf("F%d,", (int)i + 1);
        continue;
    }

    double min_dist = 100;

    for(size_t j = 0; j < matches.size(); j++ ){ 
        double dist = matches[j].distance;
        if( dist < min_dist ) 
            min_dist = dist;
    }

    if(min_dist > 50.0){
        printf("D%d,", (int)i + 1);
        continue;
    }

    double good_dist = min_dist * 3;
    for(size_t j = 0; j < matches.size(); j++ ){
        if(matches[j].distance < good_dist)
            good_matches.push_back(matches[j]);
    }

    size_t size = good_matches.size();
    if(size < 8){
        printf("M%d,", (int)i + 1);
        continue;
    }

    vector<Point2f> srcPoints(size);
    vector<Point2f> dstPoints(size);

    for(size_t j = 0; j < size; j++){
        srcPoints[j] = destination[good_matches[j].trainIdx].pt;    
        dstPoints[j] = keyPoints[i][good_matches[j].queryIdx].pt;   
    }

    vector<unsigned char> inliersMask(srcPoints.size());
    Mat H = findHomography(srcPoints, dstPoints, CV_FM_RANSAC, 3.0, inliersMask);

    vector<DMatch> inliers;
    for(size_t j = 0; j < inliersMask.size(); j++){
        if(inliersMask[j]){
            inliers.push_back(good_matches[j]);
        }
    }
    if(inliers.size() < 4){
        printf("S%d,", (int)i + 1);
        continue;
    }

    filteredMatches.push_back(inliers);
    goodIds.push_back((int)i);

    H.release();
}

printf(" good matches: ");

int best = -1;
int amount = 0;
for(size_t i = 0; i < filteredMatches.size(); i++){
    int size = (int)filteredMatches.at(i).size();
    if(size < 8) continue;

    printf("%d,", goodIds[i] + 1);

    if(amount < size){
        amount = size;
        best = i;
    }
}

if(best >= 0) printf(" best match on image: %d, keypoints: %d, ", goodIds[best] + 1, amount);

如果有人能指出我必须使用的功能或逻辑,我将非常感激!

Answer 1

你应该选择真正稳定的对应关系。我建议阅读：OpenCV 2 计算机视觉应用程序编程手册 - 第 9 章 - 使用随机样本共识匹配图像 ( http://opencv-cookbook.googlecode.com/svn/trunk/Chapter%2009/ )。