jquery/javascript检查多个子串的字符串

Question

我需要检查一个字符串是否有三个子串中的一个,如果是,则实现一个函数.我知道我可以检查一个子字符串使用if (str.indexOf("term1") >= 0)但有没有办法检查多个子字符串,而不是使用此代码的几个实例？

TIA

Answer 1

这可以动态而优雅地实现您想要做的事情

const terms = ["term1", "term2", "term3"]
const str = "very large string to check for term1, tern2, etc ..."

// check if the string has some of the terms
const result1 = terms.some(term => str.includes(term))

// check if the string has all the terms
const result2 = terms.every(term => str.includes(term))

这也使得为子字符串数组过滤字符串数组变得容易

const terms = ["term1", "term2", "term3"]
const strings = ["very large string text ....", "another large string text"] 

// filter the strings of the array that contain some of the substrings we're looking for
const result1 = strings.filter(str => terms.some(term => str.includes(term)))

// filter the strings of the array that contain all the substrings we're looking for
const result2 = strings.filter(str => terms.every(term => str.includes(term)))

Answer 2

if (/term1|term2|term3/.test("your string")) {
   //youre code
}

Answer 3

你可以使用一个循环.甚至可能创建一个这样的辅助函数:

function ContainsAny(str, items){
    for(var i in items){
        var item = items[i];
        if (str.indexOf(item) > -1){
            return true;
        }

    }
    return false;
}

你可以这样打电话:

if(ContainsAny(str, ["term1", "term2", "term3"])){
   //do something
}

Answer 4

也许这个：

if (str.indexOf("term1") >= 0 || str.indexOf("term2") >= 0 || str.indexOf("term3") >= 0) 
{
 //your code
}