HttpPost和webapi

Question

我创建了一个API,它将文件作为输入并进行处理.样本是这样的......

[HttpPost]
    public string ProfileImagePost(HttpPostedFile HttpFile)
    {

      //rest of the code
     }

然后我创建了一个客户端来消费这个如下...

 string path = @"abc.csv";
        FileStream rdr = new FileStream(path, FileMode.Open, FileAccess.Read);
        byte[] inData = new byte[rdr.Length];
        rdr.Read(inData, 0, Convert.ToInt32(rdr.Length));

        HttpWebRequest req = (HttpWebRequest)WebRequest.Create("http://localhost/abc/../ProfileImagePost");
        req.KeepAlive = false;
        req.ContentType = "multipart/form-data"; 
        req.Method = "POST";
        req.ContentLength = rdr.Length;
        req.AllowWriteStreamBuffering = true;

        Stream reqStream = req.GetRequestStream();

        reqStream.Write(inData, 0, Convert.ToInt32(rdr.Length));
        reqStream.Close();
        HttpWebResponse TheResponse = (HttpWebResponse)req.GetResponse();
        string TheResponseString1 = new StreamReader(TheResponse.GetResponseStream(), Encoding.ASCII).ReadToEnd();
        TheResponse.Close();

但是我在客户端遇到500错误.帮帮我吧.

提前完成了...

Answer 1

ASP.NET Web API无法使用HttpPostedFile.相反,你应该使用MultipartFormDataStreamProvider如图所示following tutorial.

您的客户端电话也是错误的.您已设置为ContentType,multipart/form-data但您根本不尊重此编码.您只是将文件写入请求流.

让我们举一个例子:

public class UploadController : ApiController
{
    public Task<HttpResponseMessage> Post()
    {
        if (!Request.Content.IsMimeMultipartContent())
        {
            throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);
        }

        string root = HostingEnvironment.MapPath("~/App_Data");
        var provider = new MultipartFormDataStreamProvider(root);

        // Read the form data
        return Request.Content.ReadAsMultipartAsync(provider).ContinueWith(t =>
        {
            // This illustrates how to get the file names.
            foreach (MultipartFileData file in provider.FileData)
            {
                Trace.WriteLine(file.Headers.ContentDisposition.FileName);
                Trace.WriteLine("Server file path: " + file.LocalFileName);
            }
            return Request.CreateResponse(HttpStatusCode.OK);
        }, TaskScheduler.FromCurrentSynchronizationContext());
    }
}

然后你可以用a HttpClient来调用这个API:

using System;
using System.IO;
using System.Net.Http;
using System.Net.Http.Headers;

class Program
{
    static void Main(string[] args)
    {
        using (var client = new HttpClient())
        using (var content = new MultipartFormDataContent())
        {
            client.BaseAddress = new Uri("http://localhost:16724/");
            var fileContent = new ByteArrayContent(File.ReadAllBytes(@"c:\work\foo.txt"));
            fileContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment")
            {
                FileName = "Foo.txt"
            };
            content.Add(fileContent);
            var result = client.PostAsync("/api/upload", content).Result;
            Console.WriteLine(result.StatusCode);
        }
    }
}