Jak*_*ake 0 c# task-parallel-library
给定以下代码,是否可以为实例定义调度程序,创建和继续设置Task doThing?
我希望能够安排多个实例,doThing以便它们实际上只从其他实例运行(即使它们正在等待其他子任务).
private static async Task doThing(object i)
{
Console.WriteLine("in do thing {0}", (int)i);
await Task.Delay(TimeSpan.FromSeconds(5));
Console.WriteLine("out of do thing {0}", (int)i);
}
static void Main(string[] args)
{
CancellationTokenSource source = new CancellationTokenSource();
ConcurrentExclusiveSchedulerPair pair = new ConcurrentExclusiveSchedulerPair(TaskScheduler.Current);
Task Task1 = Task.Factory.StartNew((Func<object,Task>)doThing, 1, source.Token, TaskCreationOptions.AttachedToParent, pair.ExclusiveScheduler).Unwrap();
Task Task2 = Task.Factory.StartNew((Func<object, Task>)doThing, 2, source.Token, TaskCreationOptions.AttachedToParent, pair.ExclusiveScheduler);
Task Task3 = doThing(3);
Task Task4 = Task.Factory.StartNew(async (i) =>
{
Console.WriteLine("in do thing {0}", (int)i);
await Task.Delay(TimeSpan.FromSeconds(5));
Console.WriteLine("out of do thing {0}", (int)i);
}, 4, source.Token, TaskCreationOptions.None, pair.ExclusiveScheduler);
Task.WaitAll(Task1, Task2, Task3, Task4);
Console.ReadKey();
return;
}
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TPL TaskSchedulers一次只能看到异步方法的一个同步段,因此您不能仅使用调度程序来完成.但你可以使用更高级别的原语来做到这一点.我经常使用的是TPL Dataflow.
首先,安装NuGet包:
Install-Package Microsoft.Tpl.Dataflow
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然后使用此代码:
private static async Task doThing(object i) {
Console.WriteLine("in do thing {0}", (int)i);
await Task.Delay(TimeSpan.FromSeconds(5));
Console.WriteLine("out of do thing {0}", (int)i);
}
static void Main(string[] args) {
CancellationTokenSource source = new CancellationTokenSource();
var exclusivityBlock = new ActionBlock<Func<Task>>(f => f(), new ExecutionDataflowBlockOptions { CancellationToken = source.Token }};
exclusivityBlock.Post(() => doThing(1));
exclusivityBlock.Post(() => doThing(2));
exclusivityBlock.Post(() => doThing(3));
exclusivityBlock.Post(
async () => {
Console.WriteLine("in do thing {0}", 4);
await Task.Delay(TimeSpan.FromSeconds(5));
Console.WriteLine("out of do thing {0}", 4);
});
exclusivityBlock.Complete();
exclusivityBlock.Completion.Wait();
Console.WriteLine("Done");
Console.ReadKey();
return;
}
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此代码缺少每个已发布工作项的单个任务.如果这很重要,您可以使用此示例:
internal static class Program {
private static async Task doThing(object i) {
Console.WriteLine("in do thing {0}", (int)i);
await Task.Delay(TimeSpan.FromSeconds(5));
Console.WriteLine("out of do thing {0}", (int)i);
}
private static void Main(string[] args) {
CancellationTokenSource source = new CancellationTokenSource();
var exclusivityBlock = CreateTrackingBlock<Func<Task>>(
f => f(), new ExecutionDataflowBlockOptions { CancellationToken = source.Token });
var task1 = exclusivityBlock.PostWithCompletion(() => doThing(1));
var task2 = exclusivityBlock.PostWithCompletion(() => doThing(2));
var task3 = exclusivityBlock.PostWithCompletion(() => doThing(3));
var task4 = exclusivityBlock.PostWithCompletion(
async () => {
Console.WriteLine("in do thing {0}", 4);
await Task.Delay(TimeSpan.FromSeconds(5));
Console.WriteLine("out of do thing {0}", 4);
});
Task.WaitAll(task1, task2, task3, task4);
Console.WriteLine("Done");
Console.ReadKey();
return;
}
private static ActionBlock<Tuple<T, TaskCompletionSource<object>>> CreateTrackingBlock<T>(Func<T, Task> action, ExecutionDataflowBlockOptions options = null) {
return new ActionBlock<Tuple<T, TaskCompletionSource<object>>>(
async tuple => {
try {
await action(tuple.Item1);
tuple.Item2.TrySetResult(null);
} catch (Exception ex) {
tuple.Item2.TrySetException(ex);
}
},
options ?? new ExecutionDataflowBlockOptions());
}
internal static Task PostWithCompletion<T>(this ActionBlock<Tuple<T, TaskCompletionSource<object>>> block, T value) {
var tcs = new TaskCompletionSource<object>();
var tuple = Tuple.Create(value, tcs);
block.Post(tuple);
return tcs.Task;
}
}
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但请注意,这只是一点费力,因为Dataflow主要不是为跟踪个别提交而是为了跟踪整个流程.因此,尽管上述工作正常,但Stephen Cleary的回答可能更简单,因此更为可取.
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