use*_*116 4 html django ajax jquery lighttpd
所以我一直在寻找这个答案,我发现的大多数答案要么模糊,要么高于我的编程知识.
我想要做的是在网页quad_relay.html上创建一个按钮
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.o$
<html xmlns="http://www.w3.org/1999/xhtml">
</script>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
</head>
<body>
<h1>Quad Web Relay</h1>
<div>Relay 1:
<input type="button" value="Toggle" id="toggle1" />
</div>
</body>
</head>
</html>
单击该按钮时,我希望它运行python脚本set_gpio.py
def set_pins_high():
fp = open("/sys/class/gpio/gpio"+pin+"/value","w")
fp.write(str(1))
fp.close()
def set_pins_low():
fp1 = open("/sys/class/gpio/gpio"+pin+"/value","w")
fp1.write(str(0))
fp1.close()
for pin in pins:
for x in range (0,2):
set_pins_high()
time.sleep(0.5)
set_pins_low()
time.sleep(0.5)
该网页位于运行Django的lighttpd服务器上.我安装了jQuery和AJAX,我知道它们是我需要采取的路线,但是每次尝试它都不起作用.有人能帮助我吗？
谢谢!
你必须做一些修改:
在您的HTML文件中:
<div>Relay 1:
<form action= '{% url my_view_name%}' method="POST">
<input type="submit" value="Toggle" id="toggle1" />
</form>
</div>
在urls.py中
url(r'whatever^$', 'core.views.my_view',name='my_view_name'),
在views.py中:
def my_view(request):
if request.method == 'POST':
import set_gpio
#Do your stuff ,calling whatever you want from set_gpio.py
return #Something, normally a HTTPResponse, using django