Flask Gunicorn app无法让__name__等于'__main__'

Question

我有这个来自/home/myname/myapp/app.py:

from flask import Flask

app = Flask(__name__)

print __name__

@app.route('/')
def index():
    return "Hello world!"

if __name__ == '__main__':
    print 'in if'
    app.run()

当我跑:

$ gunicorn app:app -b 127.0.0.2:8000

它说:

2013-03-01 11:26:56 [21907] [INFO] Starting gunicorn 0.17.2
2013-03-01 11:26:56 [21907] [INFO] Listening at: http://127.0.0.2:8000 (21907)
2013-03-01 11:26:56 [21907] [INFO] Using worker: sync
2013-03-01 11:26:56 [21912] [INFO] Booting worker with pid: 21912
app

所以该__name__应用程序是app.不__main__喜欢我需要它来运行if语句.
我试着__init__.py在目录中放空.这是我的nginx sites-enabled default:

server {
        #listen   80; ## listen for ipv4; this line is default and implied
        #listen   [::]:80 default_server ipv6only=on; ## listen for ipv6

        root /home/myname/myapp;

        # Make site accessible from http://localhost/
        server_name localhost;

        location / {
                proxy_pass http://127.0.0.2:8000;
        }
}

编辑

... 当我访问该网站时,此应用程序确实打印'Hello world'.关键是我需要__name__平等'__main__'.我也想知道它为什么没有以及如何使它平等__main__.

编辑2

......我只是得到了我不需要的顿悟,app.run()因为这就是Gunicorn的用途.咄.但我还是想弄明白为什么__name__不是'__main__'

Answer 1

Python设置__name__为"__main__"脚本是Python解释器的入口点.由于Gunicorn导入脚本,它正在运行该脚本将不是入口点,所以不会__name__设置为"__main__".