对另一个控制器中的codeigniter使用离子身份验证

Question

我正在尝试使用codeigniter构建一个Web应用程序.我已经安装了Ion Auth作为我的身份验证模型.

默认的Auth.php控制器对用户进行身份验证并设置会话.

<?php defined('BASEPATH') OR exit('No direct script access allowed');

class Auth extends CI_Controller {



    function __construct()
    {
        parent::__construct();
        $this->load->library('ion_auth');
        $this->load->library('session');
        $this->load->library('form_validation');
        $this->load->helper('url');

        $data['title']="Login Page";
        $this->load->view("view_site_header",$data);

        // Load MongoDB library instead of native db driver if required
        $this->config->item('use_mongodb', 'ion_auth') ?
        $this->load->library('mongo_db') :

        $this->load->database();    

        $this->form_validation->set_error_delimiters($this->config->item('error_start_delimiter', 'ion_auth'), $this->config->item('error_end_delimiter', 'ion_auth'));
    }

    //redirect if needed, otherwise display the user list
    function index()
    {
        // if not logged in - go to home page
        if (!$this->ion_auth->logged_in())
        {
            //redirect them to the login page
            redirect('auth/login', 'refresh');
        }
        // if user is an admin go to this page
        elseif ($this->ion_auth->is_admin())
        {
            // if an admin, go to admin area

            //set the flash data error message if there is one
            $this->data['message'] = (validation_errors()) ? validation_errors() : $this->session->flashdata('message');

            //list the users
            $this->data['users'] = $this->ion_auth->users()->result();
            foreach ($this->data['users'] as $k => $user)
            {
                $this->data['users'][$k]->groups = $this->ion_auth->get_users_groups($user->id)->result();
            }

            $this->_render_page('auth/view_users', $this->data);                
        }   else
    {
        //redirect them to the default home page 
        $data['title']="IMS Home Page";
        $this->load->view("generic/view_site_header",$data);
        $this->load->view("generic/view_generic_nav");
        $this->load->view("generic/view_content_generic");
        $this->load->view("view_site_footer");
    }
}

我想要做的是为我的应用程序逻辑创建一个新的控制器,并让auth控制器进行身份验证.

如何在访问新控制器时使用auth控制器确保用户登录？此外,我需要为新控制器提供ession信息.

我的新控制器master_data具有以下代码:

<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');

class Masterdata extends CI_Controller{

    function index ()
    {
            $data['title']="Master Data Home Page";
            $this->load->view("master_data/view_master_data_header",$data);
            $this->load->view("master_data/view_master_data_nav");
            $this->load->view("master_data/view_content_master_data_home");
            $this->load->view("master_data/view_master_data_footer");

            echo $this->session->userdata('username');



    }
}

显然这echo $this->session->userdata('username');不起作用,因为新控制器不知道auth控制器会话.

任何帮助一如既往的赞赏.

亲切的问候,

Answer 1

首先自动加载ion_auth库.如果您只是想检查用户是否已登录,只需在每个控制器的构造函数中检查它

public function __construct() {  
    parent::__construct();

    if (!$this->ion_auth->logged_in()) {
       // redirect to login view
    } 
}

如果您碰巧有多个组,您可以在application/core/MY_controller中创建一个新的控制器.该控制器将检查用户是否已登录.您可以扩展此基本控制器以创建新控制器.给出了一个非常好的解释作者:David john .查看此链接.