In [35]: test = pd.DataFrame({'a':range(4),'b':range(4,8)})
In [36]: test
Out[36]:
a b
0 0 4
1 1 5
2 2 6
3 3 7
In [37]: for i in test['a']:
....: print i
....:
0
1
2
3
In [38]: for i,j in test:
....: print i,j
....:
------------------------------------------------------------
Traceback (most recent call last):
File "<ipython console>", line 1, in <module>
ValueError: need more than 1 value to unpack
In [39]: for i,j in test[['a','b']]:
....: print i,j
....:
------------------------------------------------------------
Traceback (most recent call last):
File "<ipython console>", line 1, in <module>
ValueError: need more than 1 value to unpack
In [40]: for i,j in [test['a'],test['b']]:
....: print i,j
....:
------------------------------------------------------------
Traceback (most recent call last):
File "<ipython console>", line 1, in <module>
ValueError: too many values to unpack
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HYR*_*YRY 25
使用DataFrame.itertuples()方法:
for a, b in test.itertuples(index=False):
print a, b
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dre*_*cko 11
您可以使用zip(这是蟒蛇3人,可以从进口itertools为izip在Python 2.7):
for a,b in zip(test.a, test.b):
print(a,b)
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for a,b in izip(test.a, test.b):
print a,b
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您还可以使用.iterrows()方法。它返回Index和Series每行:
test = DataFrame({'a':range(4),'b':range(4,8)})
for idx, series in test.iterrows():
print series['a'], series['b']
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尝试,
for i in test.index : print test['a'][i], test['b'][i]
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为你带来,
0 4
1 5
2 6
3 7
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