如何确定表空间oracle 11g的大小

use*_*594 11 oracle11g tablespace

我有一个包含三个表的数据库.我需要将历史分区数据移动到其他模式现在我计划创建新的"历史"表.我不知道如何衡量分区和子分区的大小.你能帮我吗?请提出一些建议.

Thanxs提前.娄

Thi*_*ATR 35

以下查询可用于确定表空间和其他参数:

select df.tablespace_name "Tablespace",
       totalusedspace "Used MB",
       (df.totalspace - tu.totalusedspace) "Free MB",
       df.totalspace "Total MB",
       round(100 * ( (df.totalspace - tu.totalusedspace)/ df.totalspace)) "Pct. Free"
  from (select tablespace_name,
               round(sum(bytes) / 1048576) TotalSpace
          from dba_data_files 
         group by tablespace_name) df,
       (select round(sum(bytes)/(1024*1024)) totalusedspace,
               tablespace_name
          from dba_segments 
         group by tablespace_name) tu
 where df.tablespace_name = tu.tablespace_name 
   and df.totalspace <> 0;
Run Code Online (Sandbox Code Playgroud)

资料来源:https://community.oracle.com/message/1832920

对于您的情况,如果您想知道分区名称及其大小,只需运行此查询:

select owner,
       segment_name,
       partition_name,
       segment_type,
       bytes / 1024/1024 "MB" 
  from dba_segments 
 where owner = <owner_name>;
Run Code Online (Sandbox Code Playgroud)


Gur*_*tia 13

其中一种方法是使用下面的SQL查询

--Size of All Table Space

--1. Used Space
SELECT TABLESPACE_NAME,TO_CHAR(SUM(NVL(BYTES,0))/1024/1024/1024, '99,999,990.99') AS "USED SPACE(IN GB)" FROM USER_SEGMENTS GROUP BY TABLESPACE_NAME
--2. Free Space
SELECT TABLESPACE_NAME,TO_CHAR(SUM(NVL(BYTES,0))/1024/1024/1024, '99,999,990.99') AS "FREE SPACE(IN GB)" FROM   USER_FREE_SPACE GROUP BY TABLESPACE_NAME

--3. Both Free & Used
SELECT USED.TABLESPACE_NAME, USED.USED_BYTES AS "USED SPACE(IN GB)",  FREE.FREE_BYTES AS "FREE SPACE(IN GB)"
FROM
(SELECT TABLESPACE_NAME,TO_CHAR(SUM(NVL(BYTES,0))/1024/1024/1024, '99,999,990.99') AS USED_BYTES FROM USER_SEGMENTS GROUP BY TABLESPACE_NAME) USED
INNER JOIN
(SELECT TABLESPACE_NAME,TO_CHAR(SUM(NVL(BYTES,0))/1024/1024/1024, '99,999,990.99') AS FREE_BYTES FROM  USER_FREE_SPACE GROUP BY TABLESPACE_NAME) FREE
ON (USED.TABLESPACE_NAME = FREE.TABLESPACE_NAME);
Run Code Online (Sandbox Code Playgroud)