Lug*_*ino 4 jquery jquery-select2
我有一个问题是使用ajax调用设置方法initSelection,我返回"undefined".我检查了ajax调用返回正确的结果..我不知道如何设置回调方法以确保选择'预设值.
function mediaFormatResult(media) {
var markup = "<div class='media-title'>" + media.name + ", " + media.prov + " (" + media.region + ")</div>";
return markup;
}
function mediaFormatSelection(media) {
return media.name +", " + media.prov + " (" + media.region + ")";
}
$field = $('#comune');
$($field).select2({
placeholder: "Seleziona il tuo comune",
minimumInputLength: 3,
initSelection: function(element, callback) {
return $.ajax({
type: "POST",
url: "myurl",
dataType: 'json',
data: { id: (element.val())},
success: function(data){
//results: data.results;
}
}).done(function(data) {
//console.log(data);
callback(data);
});
},
ajax: {
quietMillis: 100,
url: "myurl",
dataType: 'json',
type: 'POST',
data: function (term, page) {
return {
q: term,
page_limit: 10
};
},
results: function (data, page) {
return {results: data.results};
}
},
formatResult: mediaFormatResult,
formatSelection: mediaFormatSelection,
formatNoMatches: function () { return "Nessun risultato trovato!";},
formatSearching: function () { return "Ricerco.."; },
formatInputTooShort: function(input, min) {return "Inserire "+ (min - input.length) + " caratteri.";},
dropdownCssClass: "bigdrop",
});
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有什么不对吗?
vla*_*iov 12
注意,您发送给回调函数的数据需要是一个具有id和text属性的对象.
这对我有用:
initSelection: function(element, callback) {
var id;
id = $(element).val();
if (id !== "") {
return $.ajax({
url: url,
type: "POST",
dataType: "json",
data: {
id: id
}
}).done(function(data) {
var results;
results = [];
results.push({
id: data.id,
text: data.name
});
callback(results[0]);
});
}
}
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