JPA 2 Criteria API，儿童计数标准

Question

我正在尝试实现类似的东西：

SELECT c.*, asCount.assetCount
FROM Company c
LEFT JOIN (
    SELECT company_id, COUNT(*) as assetCount 
    FROM Asset 
    GROUP BY company_id) asCount
ON c.id = asCount.company_id

问题：如何使用 JPA 2 Criteria 来实现这一点？

我可以单独获取 asCount 结果，但不知道如何将其加入公司

CriteriaBuilder builder = em.getCriteriaBuilder();
CriteriaQuery<Tuple> cq = builder.createTupleQuery();
Root<Asset> asset = cq.from(Asset.class);
cq.multiselect(asset.<Company>get("company").<Long>get("id").alias("id"), builder.count(asset).alias("assetCount"));
cq.groupBy( asset.<Company>get("company").<Long>get("id") );

Query query = em.createQuery(cq);
List<Tuple> results = query.getResultList();

提前致谢。

PS
1. 有一个类似的线程使用 Hibernate API 询问子项计数： Hibernate 子项计数标准
2. 描述该主题的另一个有用线程：JPA CriteriaBuilder - 按一对多关系中关联实体的数量排序

Answer 1

好吧，我自己找到了解决方案。希望它对其他人有帮助:)

CriteriaQuery<Tuple> cq = builder.createTupleQuery();
Root<Company> company = cq.from(Company.class);
Join<Company, Asset> secondTable = company.join("assets", JoinType.LEFT);
cq.multiselect(company.<String>get("id").alias("id"), builder.count(secondTable).alias("assetCount"));
cq.groupBy( company.<Long>get("id") );

Query query = em.createQuery(cq);
List<Tuple> results = query.getResultList();