我在编写SQL查询时遇到困难,该查询会将account_no正确分组并减去金额.
首先我写了这个查询,它更新一切正常,除了ACCOUNT_NO A-102应该最终为4500而不是两个不同的正确余额.
select transactions.account_no, account.balance, transactions.amount,
(account.balance + transactions.amount) AS "CORRECT BALANCE"
from transactions, account
where account.account_no = transactions.account_no;
ACCOUNT_NO| BALANCE | AMOUNT | CORRECTBALANCE
A-102 | 4000 | 2000 | 6000
A-102 | 4000 | -1500 | 2500
A-222 | 8000 | -1000 | 7000
A-305 | 2000 | 1300 | 3300
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我试图通过account_no进行求和并进行分组,但我无法弄清楚如何使用这两个表进行此操作.这只是我尝试但无法开始工作的东西.
select transactions.account_no, SUM(transactions.amount)
from transactions
group by transactions.account_no;
ACCOUNT_NO| SUM(TRANSACTIONS.AMOUNT)
A-305 | 1300
A-102 | 500
A-222 | -1000
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预期结果应该是:
ACCOUNT_NO| BALANCE | AMOUNT | CORRECTBALANCE
A-102 | 4000 | 500 | 4500
A-222 | 8000 | -1000 | 7000
A-305 | 2000 | 1300 | 3300
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这是因为账户A-102有两个不同的金额,但来自相同的余额.
对于您的查询,要将两行分组在一行上,您可以尝试对帐号和余额进行分组:
SELECT T.account_no
,A.balance
,SUM(T.amount) AS TotalAmount
,(A.balance + SUM(T.amount)) AS "CORRECT BALANCE"
FROM transactions AS T
INNER JOIN account AS A ON T.account_no = A.account_no
GROUP BY T.account_no, A.balance;
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(顺便说一下,我使用ANSI连接而不是'旧'连接表的方式,因为你用这种方式做得更清楚.)
编辑
为了使事情更清楚一点,我做了一个SQL小提琴.这或多或少正确地代表了您的情况吗?
EDIT2
Kaf评论说,上述查询不会显示没有交易的任何账户.这可能是你想要的,但如果不是你可以像这样切换连接表:
SELECT A.account_no
,A.balance
,SUM(T.amount) AS TotalAmount
,(A.balance + SUM(T.amount)) AS "CORRECT BALANCE"
FROM account AS A
LEFT OUTER JOIN transactions AS T ON T.account_no = A.account_no
GROUP BY A.account_no, A.balance;
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