在if语句中声明的变量会导致"未定义的变量"

Question

我希望在if语句中定义变量在Sass中起作用但不幸的是我得到的错误是该变量未定义.这是我尝试过的:

@for !i from 1 through 9
    !foo = #000
    @if !i == 1
        !bg_color = #009832
    @if !i == 2
        !bg_color = #195889
    ...

    #bar#{!i} 
        color: #{!foo}
        background-color: #{!bg_color}

使用此代码,我会收到以下错误:

未定义的变量:"!bg_color".

Answer 1

Sass变量仅在声明它们的缩进级别和嵌套在它下面的缩进级别可见.所以你只需要在for循环之外声明!bg_color:

!bg_color = #FFF
@for !i from 1 through 9
    !foo = #000
    @if !i == 1
        !bg_color = #009832
    @if !i == 2
        !bg_color = #195889

    #bar#{!i} 
        color: #{!foo}
        background-color: #{!bg_color}

你会得到以下css:

#bar1 {
  color: black;
  background-color: #009832; }

#bar2 {
  color: black;
  background-color: #195889; }

#bar3 {
  color: black;
  background-color: #195889; }

#bar4 {
  color: black;
  background-color: #195889; }

#bar5 {
  color: black;
  background-color: #195889; }

#bar6 {
  color: black;
  background-color: #195889; }

#bar7 {
  color: black;
  background-color: #195889; }

#bar8 {
  color: black;
  background-color: #195889; }

#bar9 {
  color: black;
  background-color: #195889; }