如何将通用JObject转换为camelCase普通json字符串?我尝试过使用JsonSerializerSettings但不起作用(Newtonsoft.Json 4.5.11)
[Test]
public void should_convert_to_camel_case()
{
var serializer = JsonSerializer.Create(new JsonSerializerSettings()
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
});
var jo = new JObject();
jo["CamelCase"] = 1;
var stringWriter = new StringWriter();
var writer = new JsonTextWriter(stringWriter);
serializer.Serialize(writer,jo);
var serialized = stringWriter.ToString();
Assert.AreEqual("{\"camelCase\":1}", serialized);
}
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更新 根据http://json.codeplex.com/workitem/23853无法完成(tnx到@nick_w的链接)
小智 36
这个问题从JObject开始,想要使用一个基于驼峰的JSON对象.如果你实际上是从一个对象开始并想要一个已经传承的JObject,那么你可以这样做:
var serializer = new JsonSerializer()
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
};
var jo = JObject.FromObject(someDataContract, serializer);
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由此产生的'jo'将是camelcased.
nic*_*k_w 14
根据这个Json.NET问题,当以JObject这种方式序列化时,合约解析器会被忽略:
在序列化JObject时,合同解析器似乎被忽略了.当然这不应该是怎么回事?
由JamesNK 于2013年1月30日上午8:50 关闭
这确实有意义,但我担心这是一个太大的突破性变化.
受该页面上的变通方法的启发,您可以执行以下操作:
var jo = new JObject();
jo["CamelCase"] = 1;
string json = JsonConvert.SerializeObject(jo);
var jObject = JsonConvert.DeserializeObject<ExpandoObject>(json);
var settings = new JsonSerializerSettings()
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
};
var serialized = JsonConvert.SerializeObject(jObject, settings);
Assert.AreEqual("{\"camelCase\":1}", serialized);
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编辑:
关于这个的好点Dictionary<string, object>.所以这样做会跳过额外的JsonConvert.SerializeObject,但它也减轻了对它的需求ExpandoObject,这对于使用.NET 3.5很重要.
Dictionary<string, object> jo = new Dictionary<string, object>();
jo.Add("CamelCase", 1);
var settings = new JsonSerializerSettings()
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
};
var serialized = JsonConvert.SerializeObject(jo, settings);
Assert.AreEqual("{\"camelCase\":1}", serialized);
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小智 6
由于这个 2013年5月8日的博客文章由詹姆斯·牛顿国王关于5.0版本Json.NET的,这已讨论了加入"DefaultSettings"的.该页面的示例如下,但请阅读页面以获取第三方库的详细信息.
// settings will automatically be used by JsonConvert.SerializeObject/DeserializeObject
JsonConvert.DefaultSettings = () => new JsonSerializerSettings
{
Formatting = Formatting.Indented,
ContractResolver = new CamelCasePropertyNamesContractResolver()
};
Employee e = new Employee
{
FirstName = "Eric",
LastName = "Example",
BirthDate = new DateTime(1980, 4, 20, 0, 0, 0, DateTimeKind.Utc),
Department = "IT",
JobTitle = "Web Dude"
};
string json = JsonConvert.SerializeObject(e);
// {
// "firstName": "Eric",
// "lastName": "Example",
// "birthDate": "1980-04-20T00:00:00Z",
// "department": "IT",
// "jobTitle": "Web Dude"
// }
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