从C#中的.resx文件中读取字符串

Question

如何在c#中读取.resx文件中的字符串？请寄给我指导.一步步

Answer 1

除非您从外部资源加载,否则不应该需要资源管理器.对于大多数事情,假设您已经创建了一个项目(DLL,WinForms,等等),您只需使用项目命名空间,"资源"和资源标识符.例如:

假设一个项目命名空间:UberSoft.WidgetPro

你的resx包含:

你可以使用:

Ubersoft.WidgetPro.Properties.Resources.RESPONSE_SEARCH_WILFRED

Answer 2

此示例来自ResourceManager.GetString()上的MSDN页面:

// Create a resource manager to retrieve resources.
ResourceManager rm = new ResourceManager("items", Assembly.GetExecutingAssembly());

// Retrieve the value of the string resource named "welcome".
// The resource manager will retrieve the value of the  
// localized resource using the caller's current culture setting.
String str = rm.GetString("welcome");

Answer 3

试试这个,对我有用..简单

假设您的资源文件名是"TestResource.resx",并且您想要动态传递密钥,

string resVal = TestResource.ResourceManager.GetString(dynamicKeyVal);

添加命名空间

using System.Resources;

Answer 4

打开.resx文件并将"Access Modifier"设置为Public.

var <Variable Name> = Properties.Resources.<Resource Name>

Answer 5

假设在项目属性下使用Visual Studio添加了.resx文件,则访问字符串的方法更容易且更不容易出错.

1. 在解决方案资源管理器中展开.resx文件应显示.Designer.cs文件.
2. 打开时,.Designer.cs文件具有Properties命名空间和内部类.对于此示例,假设该类名为Resources.

3. 然后访问字符串就像这样简单:

   var resourceManager = JoshCodes.Core.Testing.Unit.Properties.Resources.ResourceManager;
   var exampleXmlString = resourceManager.GetString("exampleXml");
   

4. 替换JoshCodes.Core.Testing.Unit为项目的默认命名空间.

5. 将"exampleXml"替换为字符串资源的名称.

Answer 6

接下来是@JeffH的回答,我建议使用typeof()比字符串程序集名称.

    var rm = new ResourceManager(typeof(YourAssembly.Properties.Resources));
    string message = rm.GetString("NameOfKey", CultureInfo.CreateSpecificCulture("ja-JP"));

Answer 7

如果由于某种原因您无法将资源文件放在App_GlobalResources中,则可以使用ResXResourceReader或XML Reader直接打开资源文件.

以下是使用ResXResourceReader的示例代码:

   public static string GetResourceString(string ResourceName, string strKey)
   {


       //Figure out the path to where your resource files are located.
       //In this example, I'm figuring out the path to where a SharePoint feature directory is relative to a custom SharePoint layouts subdirectory.  

       string currentDirectory = Path.GetDirectoryName(HttpContext.Current.Server.MapPath(HttpContext.Current.Request.ServerVariables["SCRIPT_NAME"]));

       string featureDirectory = Path.GetFullPath(currentDirectory + "\\..\\..\\..\\FEATURES\\FEATURENAME\\Resources");

       //Look for files containing the name
       List<string> resourceFileNameList = new List<string>();

       DirectoryInfo resourceDir = new DirectoryInfo(featureDirectory);

       var resourceFiles = resourceDir.GetFiles();

       foreach (FileInfo fi in resourceFiles)
       {
           if (fi.Name.Length > ResourceName.Length+1 && fi.Name.ToLower().Substring(0,ResourceName.Length + 1) == ResourceName.ToLower()+".")
           {
               resourceFileNameList.Add(fi.Name);

           }
        }

       if (resourceFileNameList.Count <= 0)
       { return ""; }


       //Get the current culture
       string strCulture = CultureInfo.CurrentCulture.Name;

       string[] cultureStrings = strCulture.Split('-');

       string strLanguageString = cultureStrings[0];


       string strResourceFileName="";
       string strDefaultFileName = resourceFileNameList[0];
       foreach (string resFileName in resourceFileNameList)
       {
           if (resFileName.ToLower() == ResourceName.ToLower() + ".resx")
           {
               strDefaultFileName = resFileName;
           }

           if (resFileName.ToLower() == ResourceName.ToLower() + "."+strCulture.ToLower() + ".resx")
           {
               strResourceFileName = resFileName;
               break;
           }
           else if (resFileName.ToLower() == ResourceName.ToLower() + "." + strLanguageString.ToLower() + ".resx")
           {
               strResourceFileName = resFileName;
               break;
           }
       }

       if (strResourceFileName == "")
       {
           strResourceFileName = strDefaultFileName;
       }



       //Use resx resource reader to read the file in.
       //https://msdn.microsoft.com/en-us/library/system.resources.resxresourcereader.aspx

       ResXResourceReader rsxr = new ResXResourceReader(featureDirectory + "\\"+ strResourceFileName);         

       //IDictionaryEnumerator idenumerator = rsxr.GetEnumerator();
       foreach (DictionaryEntry d in rsxr)
       {
           if (d.Key.ToString().ToLower() == strKey.ToLower())
           {
               return d.Value.ToString();
           }
       }


       return "";
   }

Answer 8

将资源(Name:ResourceName和Value:ResourceValue)添加到解决方案/程序集后,只需使用"Properties.Resources.ResourceName"即可获取所需的资源.

Answer 9

我通过Visual Studio添加了.resx文件.这创建了一个designer.cs具有属性的文件,可以立即返回我想要的任何键的值.例如,这是设计器文件中的一些自动生成的代码.

/// <summary>
///   Looks up a localized string similar to When creating a Commissioning change request, you must select valid Assignees, a Type, a Component, and at least one (1) affected unit..
/// </summary>
public static string MyErrorMessage {
    get {
        return ResourceManager.GetString("MyErrorMessage", resourceCulture);
    }
}

这样,我就能做到:

string message = Errors.MyErrorMessage;

通过Visual Studio创建Errors的Errors.resx文件在哪里,MyErrorMessage是关键.

Answer 10

我直接将我的资源文件添加到我的项目中,因此我能够使用resx文件名访问内部的字符串.

示例:在Resource1.resx中,键"resourceKey" - >字符串"dataString".要获取字符串"dataString",我只需要放置Resource1.resourceKey.

可能有理由不这样做,我不知道,但它对我有用.