是否可以在Jasmine.Js中检查toEqual中的多个类型？

Question

我是Jasmine的新手,遇到了我希望String或null的情况.我尝试做一个或在toEqual之内,但我看到一些奇怪的结果让我相信我会以错误的方式进行.这种情况的最佳方法是什么？

也许我只是在考虑我的测试错误.我是否应该放弃一个测试以测试这两种情况的想法？

describe("Jasmine", function () {

    //1
    it("should be able to handle any(String) || null within toEqual for string", function () {
        expect("aString").toEqual(jasmine.any(String) || null);
    });

    //2
    it("should be able to handle any(String) || null within toEqual for null", function () {
        expect(null).toEqual(jasmine.any(String) || null);
    });

    //3
    it("should be able to handle null || any(String) within toEqual for string", function () {
        expect("aString").toEqual(null || jasmine.any(String));
    });

    //4
    it("should be able to handle null || any(String) within toEqual for null", function () {
        expect(null).toEqual(null || jasmine.any(String));
    });
});

1. 通过
2. Expected null to equal <jasmine.any(function String() { [native code] })>.
3. 通过
4. Expected null to equal <jasmine.any(function String() { [native code] })>.

我意识到还有一个toBeNull(),这可能是为什么结果如此不稳定,但没有"或"链接我不知道如何合并它.

(运行Jasmine 1.3.1修订版1354556913)

解决了!如果有人有兴趣,请在下方提供完整

describe("Jasmine", function () {

    beforeEach(function () {
        this.addMatchers({

            toBeStringOrNull: function () {
                var actual = this.actual;

                this.message = function () {
                    return "Expected " + actual + " to be either string or null";
                };

                return typeof actual === 'string' || actual instanceof String || actual === null;
            }

        });
    });

    //1
    it("should be able to handle any(String) || null within toEqual for string", function () {
        expect("aString").toBeStringOrNull();
    });

    //2
    it("should be able to handle any(String) || null within toEqual for null", function () {
        expect(null).toBeStringOrNull();
    });

    //3
    it("should be able to handle null || any(String) within toEqual for string", function () {
        expect("aString").toBeStringOrNull();
    });

    //4
    it("should be able to handle null || any(String) within toEqual for null", function () {
        expect(null).toBeStringOrNull();
    });
});

Answer 1

编写自己的自定义匹配器:

toBeStringOrNull: function() {
  var actual = this.actual;

  this.message = function () {
    return "Expected " + actual + " to be either string or null";
  }

  return typeof actual === 'string' || actual instanceof String || actual === null;
}