Flask:如何从模板目录下提供静态文件？

Question

我使用Flask并想要更改我的资产文件夹目录.这是我的文件夹结构:

/python
   /static
     /js
     /img
     /font
     /css
   /templates
     /default
       /css
       /js
       /img
   /venv
   app.py

我想将静态文件夹(js,css,font,img)下的所有文件夹移动到该文件夹下default.但当我这样做我的CSS文件和其他(js etc.)无法加载页面.我应该设置属性到我的应用程序？我也试过这个:

app = Flask(__name__,static_path="/templates/default")

但是无法做到.有另外一种方法吗？非常感谢.

更新: 当我删除上面一行中的前导斜杠时(static_path="templates/default")ValueError: urls must start with a leading slash 使用traceback 获得此错误:

Traceback (most recent call last):
  File "app.py", line 17, in <module>
    app = Flask(__name__,static_path="templates/default")
  File "/Users/ozcan/Library/Python/2.7/lib/python/site-packages/flask/app.py", line 481, in __init__
    view_func=self.send_static_file)
  File "/Users/ozcan/Library/Python/2.7/lib/python/site-packages/flask/app.py", line 63, in wrapper_func
    return f(self, *args, **kwargs)
  File "/Users/ozcan/Library/Python/2.7/lib/python/site-packages/flask/app.py", line 943, in add_url_rule
    rule = self.url_rule_class(rule, methods=methods, **options)
  File "/Users/ozcan/Library/Python/2.7/lib/python/site-packages/werkzeug/routing.py", line 550, in __init__
    raise ValueError('urls must start with a leading slash')
ValueError: urls must start with a leading slash

Answer 1

初始化app时应该是static_folder而不是static_path.

app = Flask(__name__,static_folder="/templates/default")

在模板中:

<script src="{{ url_for('static', filename='js/file.js')}}"</script>

希望能帮助到你.

Answer 2

抱歉，我误读了您的原始目录输出。您需要放入templates该static目录，因为 Flask 默认情况下会在该目录中查找静态数据。