pil用不同的颜色绘制文本

Question

您好,为ex绘制三个不同的文本,具有不同的选项:

1. text-number-1,font = arial,color = red
2. text-number-2,font = veranda,color = blue,size = 30
3. text-number-3,font = tahoma,color = green,size = 40,align = center

文字必须以新的方式排列.

def pil_image(request):
text = request.GET.get('text', None)
font = str(request.GET.get('font', 'arial'))
fontsize = int(request.GET.get('fontsize', '20'))
textcolor = str(request.GET.get('textcolor', '000'))

import Image, ImageDraw, ImageFont, textwrap

img = Image.open('media/text/transparent.png')
img = img.convert("RGBA")
datas = img.getdata()
w, h = img.size

newData = []
for item in datas:
    if item[0] == 255 and item[1] == 255 and item[2] == 255:
        newData.append((255, 255, 255, 0))
    else:
        newData.append(item)

img.putdata(newData)

draw = ImageDraw.Draw(img)
font = ImageFont.truetype("media/text/fonts/" + font + ".ttf", fontsize, encoding="unic")


margin = offset = 40
for line in textwrap.wrap(text, width=48):
    w, h = draw.textsize(line)
    draw.text((margin, offset), line, font=font, fill='#'+textcolor)
    offset += font.getsize(line)[1]

del draw 

img.save("media/text/custom.png", "PNG")

return HttpResponse("<img src='/media/text/custom.png'>");

Answer 1

当您使用RGBA颜色模式时,"fill"参数应该是具有4个数字的元组.

对于不透明的红色:

draw.text((margin, offset), line, font=font, fill=(255,0,0,255) )

Answer 2

使用颜色的十六进制值，如下所示：

draw.text((margin, offset), line, font=font, fill="#000")