Bri*_*ian 13 javascript jquery deferred jquery-deferred
我有三个函数我正在尝试运行,前两个正在做一些异步的东西,需要第三个使用的数据.我希望只有当1和2都完成时才会触发第三个函数.这是一般结构,但最终功能是在1和2结束前开始.
function run() {
var data1 = {};
var data2 = {};
$.when(first(), second()).done(constructData());
function first() {
var d = new $.Deferred();
//do a bunch of stuff async
data1 = {};
d.resolve();
}
function second() {
var d = new $.Deferred();
//do a bunch of stuff async
data2 = {};
d.resolve();
}
function constructData() {
//do stuff with data1 and data2
}
}
Run Code Online (Sandbox Code Playgroud)
答案是不立即调用构造数据
$.when(first(), second()).done(constructData);
Run Code Online (Sandbox Code Playgroud)
dfs*_*fsq 24
你应该返回promise对象.此行中也有错误:
$.when(first(), second()).done(constructData());
Run Code Online (Sandbox Code Playgroud)
它应该是
$.when(first(), second()).done(constructData); // don't call constructData immediately
Run Code Online (Sandbox Code Playgroud)
所以它们可能是:
function run() {
var data1 = {};
var data2 = {};
$.when(first(), second()).done(constructData);
function first() {
return $.Deferred(function() { // <-- see returning Deferred object
var self = this;
setTimeout(function() { // <-- example of some async operation
data1 = {func: 'first', data: true};
self.resolve(); // <-- call resolve method once async is done
}, 2000);
});
}
function second() {
return $.Deferred(function() {
var self = this;
setTimeout(function() {
data2 = {func: 'second', data: true};
self.resolve();
}, 3000);
});
}
function constructData() {
//do stuff with data1 and data2
console.log(data1, data2);
}
}
Run Code Online (Sandbox Code Playgroud)
归档时间: |
|
查看次数: |
13793 次 |
最近记录: |