在android中拒绝来电

Question

我想在android中拒绝传入,我从这些链接中看到了很多代码.

1. Android:完全掌控手机(自助终端模式),有可能吗？怎么样？

2. 如何在android中以编程方式拒绝调用

3. http://androidsourcecode.blogspot.in/2010/10/blocking-incoming-call-android.html

4. http://androidbridge.blogspot.com/2011/05/how-to-answer-incoming-call-in-android.html?showComment=1361478035090#c5468022990217431781

但是我仍然无法做到这一点,任何人都可以通过简单易行的步骤告诉我该怎么做？

Answer 1

为了拦截你的电话,你只需要:
1.制作一个名为的包裹.com.android.internal.telephony;
2.在此包中创建一个名为ITelephony的接口文件.
并在该接口文件中写入此代码.

boolean endCall();
void answerRingingCall();
void silenceRinger();

现在,在您想要拦截调用的类中BroadcastReceiver,将该类扩展为onReceive()函数并在函数中编写以下代码.

TelephonyManager tm = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
   try {
     Class c = Class.forName(tm.getClass().getName());
     Method m = c.getDeclaredMethod("getITelephony");
     m.setAccessible(true);
     telephonyService = (ITelephony) m.invoke(tm);
     Bundle bundle = intent.getExtras();
     String phoneNumber = bundle.getString("incoming_number");
     Log.d("INCOMING", phoneNumber);
     if ((phoneNumber != null)) { 
        telephonyService.endCall();
        Log.d("HANG UP", phoneNumber);
     }

   } catch (Exception e) {
     e.printStackTrace();
   }

而已.

Answer 2

提供适当的权限并添加ITelephony.java文件

private void declinePhone(Context context) throws Exception {

        try {

            String serviceManagerName = "android.os.ServiceManager";
            String serviceManagerNativeName = "android.os.ServiceManagerNative";
            String telephonyName = "com.android.internal.telephony.ITelephony";
            Class<?> telephonyClass;
            Class<?> telephonyStubClass;
            Class<?> serviceManagerClass;
            Class<?> serviceManagerNativeClass;
            Method telephonyEndCall;
            Object telephonyObject;
            Object serviceManagerObject;
            telephonyClass = Class.forName(telephonyName);
            telephonyStubClass = telephonyClass.getClasses()[0];
            serviceManagerClass = Class.forName(serviceManagerName);
            serviceManagerNativeClass = Class.forName(serviceManagerNativeName);
            Method getService = // getDefaults[29];
            serviceManagerClass.getMethod("getService", String.class);
            Method tempInterfaceMethod = serviceManagerNativeClass.getMethod("asInterface", IBinder.class);
            Binder tmpBinder = new Binder();
            tmpBinder.attachInterface(null, "fake");
            serviceManagerObject = tempInterfaceMethod.invoke(null, tmpBinder);
            IBinder retbinder = (IBinder) getService.invoke(serviceManagerObject, "phone");
            Method serviceMethod = telephonyStubClass.getMethod("asInterface", IBinder.class);
            telephonyObject = serviceMethod.invoke(null, retbinder);
            telephonyEndCall = telephonyClass.getMethod("endCall");
            telephonyEndCall.invoke(telephonyObject);

        } catch (Exception e) {
            e.printStackTrace();
            Log.d("unable", "msg cant dissconect call....");

        }

Answer 3

您将需要一个带有意图过滤器的广播接收器，我认为 ACTION_ANSWER

有关它的更多详细信息，请参见：http://developer.android.com/reference/android/content/Intent.html#ACTION_ANSWER

您可以使用清单文件或方法 registerReceiver 来注册它

更多信息在这里：http://developer.android.com/reference/android/content/Context.html#registerReceiver (android.content.BroadcastReceiver，android.content.IntentFilter)

您还需要在清单文件中指定适当的权限。

<uses-permission android:name="android.permission.READ_PHONE_STATE" />
<uses-permission android:name="android.permission.MODIFY_PHONE_STATE" />
<uses-permission android:name="android.permission.CALL_PHONE" />
<uses-permission android:name="android.permission.PROCESS_INCOMING_CALLS" />

您提供的链接非常好。你只是需要更多的耐心:)

快乐编码。