Delphi:无效的XML通过MSXML验证

Question

我试图在MSDN上重新编写一个JScript示例,以便针对某些模式验证XML.

作为第一个attmempt,我使用了示例中使用的sl-valid.xml,sl-notValid.xml和sl.xsd文件.

我的代码如下:

procedure BasicValidation(FileName: string);
var
  XML: IXMLDOMDocument2;
begin
  // Load XML and resolve externals
  XML := ComsDOMDocument.Create;
  XML.async := False;
  XML.validateOnParse := True;
  XML.resolveExternals := True;
  XML.setProperty('SelectionLanguage', 'XPath');
  XML.setProperty('SelectionNamespaces', 'xmlns:x=''urn:book''');
  XML.load(FileName);
  if XML.parseError.errorCode <> 0 then
    ShowMessage('Error parsing. Reason: ' + XML.parseError.reason)
  else
    ShowMessage('XML validation OK.');
end;

当我尝试sl-notValid.xml文件时,我仍然可以获得'XML验证'.有没有人见过这个？上述代码与JScript考试之间的根本区别是什么？http://msdn.microsoft.com/en-us/library/ms764717%28VS.85%29.aspx？

Answer 1

试试这个

procedure BasicValidation(FileName: string);
var
  XML: IXMLDOMDocument2;
begin
  XML := CoDOMDocument40.Create;
  XML.async := False;
  XML.validateOnParse := True;
  XML.resolveExternals := True;
  XML.setProperty('SelectionLanguage', 'XPath');
  XML.setProperty('SelectionNamespaces', 'xmlns:x=''urn:book''');
  XML.load(FileName);
  if XML.parseError.errorCode <> 0 then
    ShowMessage('Error parsing. Reason: ' + XML.parseError.reason)
  else
    ShowMessage('XML validation OK.');
end;

说明,您必须显式调用支持XSD架构验证的版本的构造函数(MSXML> = 4).

再见.