Pythonic方法构建组合字符串

nit*_*tin 3 python list-comprehension

我有一个列表,像这样,

a = ['dog','cat','mouse']
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我想构建一个列表,它是所有列表元素的组合,看起来像,

ans = ['cat-dog', 'cat-mouse','dog-mouse']
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这就是我提出的,

a = ['dog','cat','mouse']
ans = []
for l in (a):
    t= [sorted([l,x]) for x in a if x != l]
    ans.extend([x[0]+'-'+x[1] for x in t])
print list(set(sorted(ans)))
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是否有更简单,更pythonic的方式!

Jon*_*nts 7

订购有多重要?

>>> a = ['dog','cat','mouse']
>>> from itertools import combinations
>>> ['-'.join(el) for el in combinations(a, 2)]
['dog-cat', 'dog-mouse', 'cat-mouse']
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或者,为了匹配您的示例:

>>> ['-'.join(el) for el in combinations(sorted(a), 2)]
['cat-dog', 'cat-mouse', 'dog-mouse']
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