如何使用firebase向特殊在线用户发送警报消息

Question

我正在尝试使用javascript制作一个"FourConnect"游戏.我想,所有在线用户都有一个列表.这个列表是我在firebase网站上的例子.现在我希望我可以选择一个在线用户并向他们发送邀请来与我一起玩.所以我写了一个函数,所有用户都希望我有一个额外的div.当我点击div时,这个特殊用户应该得到一个确认框来说出okey或取消.如果用户点击该键,则该游戏应该开始.我将保存用户的名称和ID.这已经有效了.

我的问题是,我不知道如何将请求发送给其他用户.我尝试了很多,但总是确认框在我的brwoser上而不是在其他用户的浏览器上.

我在firebase页面和谷歌上寻找解决方案,但找不到任何解决我问题的方法.

我已有的代码:

  var name = prompt("Your name?", "Guest"),
      currentStatus = "? online";

  // Get a reference to the presence data in Firebase.
  var userListRef = new Firebase(connectFour.CONFIG.firebaseUrl);

  // Generate a reference to a new location for my user with push.
  var myUserRef = userListRef.push();
  var gameId = myUserRef.name();
  document.getElementById('labelGameId').innerHTML = gameId;

  beginGame({id: gameId, name: name, status: currentStatus});
  // Get a reference to my own presence status.
  var connectedRef = new Firebase('http://presence.firebaseio-demo.com/.info/connected');
  connectedRef.on("value", function(isOnline) {
    if (isOnline.val()) {
      // If we lose our internet connection, we want ourselves removed from the list.
      myUserRef.onDisconnect().remove();

      // Set our initial online status.
      setUserStatus("? online");
    } else {

      // We need to catch anytime we are marked as offline and then set the correct status. We
      // could be marked as offline 1) on page load or 2) when we lose our internet connection
      // temporarily.
      setUserStatus(currentStatus);
    }
  });
//}


  // A helper function to let us set our own state.
  function setUserStatus(status) {
    // Set our status in the list of online users.
    currentStatus = status;
    myUserRef.set({ name: name, status: status });
  }

  // Update our GUI to show someone"s online status.
  userListRef.on("child_added", function(snapshot) {
    var user = snapshot.val();
    $("#output").append($("<div/>").attr("id", snapshot.name()));
    $("#" + snapshot.name()).text(user.name + " is currently " + user.status);
    if(snapshot.name() != myUserRef.name()){
        var $invite = $('<div id="invite">invite</div>');
        $("#output").append($invite);
        $($invite).on('click', function(){
            //startGame(user);
            console.log('Gegner2: '+snapshot.name());
            console.log('Genger2Name: '+user.name);
                joinGame({id: snapshot.name(), name: user.name, status: user.status});
        });
    }

  });

  // Update our GUI to remove the status of a user who has left.
  userListRef.on("child_removed", function(snapshot) {
    $("#" + snapshot.name()).remove();
  });

  // Update our GUI to change a user"s status.
  userListRef.on("child_changed", function(snapshot) {
    var user = snapshot.val();
    $("#" + snapshot.name()).text(user.name + " is currently " + user.status);
  });
  document.onIdle = function () {
    setUserStatus("? idle");
  }
  document.onAway = function () {
    setUserStatus("? away");
  }
  document.onBack = function (isIdle, isAway) {
    setUserStatus("? online");
  }

  setIdleTimeout(5000);
  setAwayTimeout(10000);


function joinGame(opponent) {
    console.log(opponent);
    console.log(opponent.id);
    var player2ID = opponent.id; 
    myUserRef = new Firebase(connectFour.CONFIG.firebaseUrl + opponent.id);
    myUserRef.once('value', function(dataSnapshot){
        if(dataSnapshot.val()){
            beginGame({id: player2ID , name: opponent.name, status: opponent.status});
        }else{
            alert("game doesn't exist");
        }
    });

}

function beginGame(player) {
    console.log(player);
    console.log('Id spieler1: '+gameId);

    });

使用此代码,我可以单击"邀请",然后我将看到用户拥有的ID.我也想将ID发送给beginGame(),但这并没有真正起作用.

我的Firebase结构:

游戏

-InmydEpSe5oZcLZUhfU

-InrLM6uxAsoOayOgFce

  -name: "Barbara"

  -status: "away"

Answer 1

要向其他用户发送消息,您需要该用户监控Firebase中的已知位置.然后,当您想要向他们发送消息时,您只需以某种方式修改该位置,他们就会收到回调.这是一些伪代码:

var root = new Firebase(...);

//On initialization start listening for messages
root.child("users/inbound-messages").on("child_added", 
  function(newMessageSnapshot) {
    displaySomethingToTheUser(newMessageSnapshot.val());
    newMessageSnapshot.ref().remove();
  }
);

//Send a message to another user
root.child(otherUserId).child("inbound-messages").push("Hi other user!");