如何同时实现两个UIButton？

Question

我创建2个UIButton(不同的标签)并连接到1个动作但是当同时按下时,它会以小延迟触发2个动作.

- (IBAction)keysPress:(UIButton *)sender {
    UIButton *butOne = (UIButton *)[sender viewWithTag:0];
    UIButton *butTwo = (UIButton *)[sender viewWithTag:1];
    NSLog(@"BUT 1: %@ || BUT 2: %@",butOne, butTwo);
}

记录总是2次:

2013-02-19 09:37:40.933 TestActions[1107:c07] BUT 1: <UIButtonLabel: 0xca4d450; frame = (65 67; 9 19); text = 'â'; clipsToBounds = YES; opaque = NO; userInteractionEnabled = NO; layer = <CALayer: 0xca4d4c0>> || BUT 2: <UIRoundedRectButton: 0xca4d310; frame = (161 164; 139 153); opaque = NO; autoresize = RM+BM; tag = 1; layer = <CALayer: 0xca4d270>>

2013-02-19 09:37:40.935 TestActions[1107:c07] BUT 1: <UIRoundedRectButton: 0xca4c5c0; frame = (20 164; 135 153); opaque = NO; autoresize = RM+BM; layer = <CALayer: 0xca4c6b0>> || BUT 2: (null)

如何控制这种情况？2节,1次动作 - 开火1次.

Answer 1

你好像不明白它sender是什么.发件人是触发事件的按钮,您可以根据它来编程.

您需要保存对按钮的引用,然后在输入函数时将它们与发送方进行比较.

@property (nonatomic, weak) IBOutlet UIButton *butOne;
@property (nonatomic, weak) IBOutlet UIButton *butTwo;

-(IBAction)keysPress:(UIButton *)sender {
   if(sender == [self butOne]) {
       //Do button one actions
   } 

   if(sender == [self butTwo]) {
       //Do button two actions
   }
}

如果您不想保留引用并使用这些viewWithTag内容,我真的不会建议它,但如果您这样做,您可以:

- (IBAction)keysPress:(UIButton *)sender {
   UIButton *butOne = (UIButton *)[self viewWithTag:1];
   UIButton *butTwo = (UIButton *)[self viewWithTag:2];
   if(sender == butOne) {
       //Do button one actions
   } 

   if(sender == butTwo) {
       //Do button two actions
   }
}