sav*_*oob 0 php mysql sql database
我有一个简单的声明:
$update1 = mysql_query("UPDATE leads SET call = 'Call 2', user = '' WHERE ID = '$rowid'") or die(mysql_error());
Run Code Online (Sandbox Code Playgroud)
这是抛出此错误消息:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'call = 'Call 2', user = '' WHERE ID = '29657'' at line 1
Run Code Online (Sandbox Code Playgroud)
我认为通常意味着"呼叫"之前的陈述是问题,但一切对我来说都很好.有任何想法吗?
call是保留关键字.你需要在反引号中逃脱它:
$update1 = mysql_query("UPDATE leads SET `call` = 'Call 2', user = '' WHERE ID = '$rowid'") or die(mysql_error());
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
122 次 |
| 最近记录: |