具有相同键的 2 个数组元素的总和

Question

嗨，我有 2 个数组，例如

 array(a) {  [0]=> array(2) { ["count"]=> string(2) "22" ["hour"]=> string(1) "0" }
             [1]=> array(2) { ["count"]=> string(2) "17" ["hour"]=> string(1) "1" } 
             [2]=> array(2) { ["count"]=> string(2) "22" ["hour"]=> string(1) "2" } 
             [3]=> array(2) { ["count"]=> string(2) "15" ["hour"]=> string(1) "3" } 
             [4]=> array(2) { ["count"]=> string(2) "15" ["hour"]=> string(1) "4" }
            }

我有第二个数组具有不同的（计数）值

 array(b) {  [0]=> array(2) { ["count"]=> string(2) "12" ["hour"]=> string(1) "0" }
             [1]=> array(2) { ["count"]=> string(2) "36" ["hour"]=> string(1) "1" } 
             [2]=> array(2) { ["count"]=> string(2) "59" ["hour"]=> string(1) "2" } 
             [3]=> array(2) { ["count"]=> string(2) "5"  ["hour"]=> string(1) "3" } 
             [4]=> array(2) { ["count"]=> string(2) "27" ["hour"]=> string(1) "4" }
            }

你能告诉我如何获得两个数组的 [“count”] 总和并获得一个新数组，例如

 array(c) {  [0]=> array(2) { ["count"]=> string(2) "34" ["hour"]=> string(1) "0" }
             [1]=> array(2) { ["count"]=> string(2) "53" ["hour"]=> string(1) "1" } 
             [2]=> array(2) { ["count"]=> string(2) "81" ["hour"]=> string(1) "2" } 
             [3]=> array(2) { ["count"]=> string(2) "20"  ["hour"]=> string(1) "3" } 
             [4]=> array(2) { ["count"]=> string(2) "42" ["hour"]=> string(1) "4" }
            }

谢谢。

Answer 1

$result_array = array() ;

for ($i = 0, $length = count($a_array) ; $i < $length ; $i++){
  $result_array[$i] = $a_array[$i] ;
  $result_array[$i]["count"] += $b_array[$i]['count'] ;  
}

var_dump($result_array) ;