Bash脚本和行

Question

我的问题是行mysql_query.我需要:

Record 0: 2,text is text,3.23

但是我有:

Record 0: 2
Record 1: text
Record 2: is
Record 3: text
Record 4: 3.23

请帮我.

results=($(mysql --user root -proot test -Bse "select id,name from Object"));

cnt=${#results[@]}

for (( i=0 ; i<${cnt} ; i++ ))
do
    echo "Record No. $i: ${results[$i]}"

    fieldA=${results[0]};
    fieldB=${results[1]};

done

Answer 1

问题是您将输出存储mysql到数组中.现在,如果mysql返回多个记录,您将不知道记录何时结束而下一个记录开始,因为该数组将包含"扁平"数据,例如( record1_fieldA record1_fieldB record2_fieldA record2_fieldB ... )

相反,使用while循环迭代记录,如下所示:

i=0
while read fieldA fieldB
do
    echo "Record $(( i++ )): fieldA: $fieldA fieldB: $fieldB"
done < <(mysql --user root -proot test -Bse "select id,name from Object")