如何使用空格分割字符串,并使用正则表达式将前导和尾随空格忽略为单词数组？

Question

我通常在JavaScript中使用以下代码来按空格分割字符串.

"The quick brown fox jumps over the lazy dog.".split(/\s+/);
// ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog."]

这当然可以在单词之间存在多个空白字符时起作用.

"The  quick brown fox     jumps over the lazy   dog.".split(/\s+/);
// ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog."]

问题是当我有一个具有前导或尾随空格的字符串时,在这种情况下,生成的字符串数组将在数组的开头和/或结尾包含一个空字符.

"  The quick brown fox jumps over the lazy dog. ".split(/\s+/);
// ["", "The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog.", ""]

消除这些空字符是一项微不足道的任务,但如果可能的话,我宁愿在正则表达式中处理这个问题.有谁知道我可以用什么正则表达式来实现这个目标？

Answer 1

如果您对不是空格的位更感兴趣,则可以匹配非空格而不是在空格上拆分.

"  The quick brown fox jumps over the lazy dog. ".match(/\S+/g);

请注意,以下内容返回null:

"   ".match(/\S+/g)

所以最好的学习方式是:

str.match(/\S+/g) || []

Answer 2

" The quick brown fox jumps over the lazy dog. ".trim().split(/\s+/);

Answer 3

您可以匹配任何非空白序列,而不是在空格序列中进行拆分:

"  The quick brown fox jumps over the lazy dog. ".match(/\S+/g)