为什么我不能通过typeglob访问词法变量？

Question

我不明白为什么下面的例子失败了(测试2).为什么我无法从*bb glob访问变量bb？

use Test::More tests => 4;

$aa = 1;
my $bb = 2;   # HERE!
local $cc = 3;
our $dd = 4;

is(${*aa}, 1, "$ \*aa should be 1");
is(${*bb}, 2, "$ \*bb (my) should be 2");
is(${*cc}, 3, "$ \*cc (local) should be 3");
is(${*dd}, 4, "$ \*dd (our) should be 4");

输出是

1..4
ok 1 - *aa should be 1
#   Failed test '*bb (my) should be 2'
#   at untitled line 10.
#          got: undef
#     expected: '2'
# Looks like you failed 1 test of 4.
not ok 2 - *bb (my) should be 2
ok 3 - *cc (local) should be 3
ok 4 - *dd (our) should be 4

根据perl 5.16.0

谢谢

Answer 1

词法变量(用它们创建的变量my)不是符号表的一部分,因此无法通过globs访问它们.另见符号表和全局.