bot*_*bot 17 ruby ruby-on-rails carrierwave
使用Carrierwave将图像从客户端上传到Rails后端的最佳方法是什么?现在我们的iOS开发人员将文件作为base64发送,所以请求如下:
"image_data"=>"/9j/4AAQSkZJRgABAQAAAQABAAD/4QBYRXhpZgAATU0AKgAAAAgAAgESAAMAAAABAAEAAIdpAAQAAAABAAAAJgAAAAAAA6ABAAMAAAABAAEAAKACAAQAAAABAAAAHqADAAQAAAABAAAAHgAAAAD/2wBDAAEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQH/2wBDAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQH/wAARCAAeAB4DAREAAhEBAxEB/8QAHwAAAQUBAQE....
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所以,我的问题实际上是两个问题.我应该告诉他发送不同的文件格式吗?如果base64是发送这些文件的正确方法,那么我如何在carrierwave中处理它们?
Rad*_*sky 28
我认为一种解决方案可以是将解码后的数据保存到文件中,然后将此文件分配给已安装的上传器.然后摆脱那个文件.
另一个(内存中)解决方案可以是这个:
# define class that extends IO with methods that are required by carrierwave
class CarrierStringIO < StringIO
def original_filename
# the real name does not matter
"photo.jpeg"
end
def content_type
# this should reflect real content type, but for this example it's ok
"image/jpeg"
end
end
# some model with carrierwave uploader
class SomeModel
# the uploader
mount_uploader :photo, PhotoUploader
# this method will be called during standard assignment in your controller
# (like `update_attributes`)
def image_data=(data)
# decode data and create stream on them
io = CarrierStringIO.new(Base64.decode64(data))
# this will do the thing (photo is mounted carrierwave uploader)
self.photo = io
end
end
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您可以使用Carrierwave-base64 Gem轻松实现这一点,您无需自己处理数据,只需添加gem并更改模型即可
mount_uploader :file, FileUploader
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至
mount_base64_uploader :file, FileUploader
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这就是它,现在你可以很容易地说:
Attachment.create(file: params[:file])
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老问题,但我不得不做类似的事情,从通过 json 请求传递的 base64 字符串上传图像。这就是我最终做的:
#some_controller.rb
def upload_image
set_resource
image = get_resource.decode_base64_image params[:image_string]
begin
if image && get_resource.update(avatar: image)
render json: get_resource
else
render json: {success: false, message: "Failed to upload image. Please try after some time."}
end
ensure
image.close
image.unlink
end
end
#some_model.rb
def decode_base64_image(encoded_file)
decoded_file = Base64.decode64(encoded_file)
file = Tempfile.new(['image','.jpg'])
file.binmode
file.write decoded_file
return file
end
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