NSComparisonResult,如何将searchText与多个字符串进行比较？

Question

我正在使用此代码在我的tableview中搜索:

for (Actor *actorz in arr)
{     
     NSComparisonResult result = [actorz.actorNaam compare:searchText options:(NSCaseInsensitiveSearch|NSDiacriticInsensitiveSearch) range:[actorz.actorNaam rangeOfString:searchText options:(NSCaseInsensitiveSearch|NSDiacriticInsensitiveSearch)]];
     if (result == NSOrderedSame)
     {
          [self.filteredListContent addObject:actorz];
     }   
}

现在我想知道如何不仅可以将searchText与actorz.actorNaam进行比较,还可以将其与actorz.actorBeschrijving进行比较？所以我想将searchText与两个字符串进行比较..

Answer 1

如果找不到字符串,则NSString返回an 的搜索方法NSRange设置为location NSNotFound.

因此,您可以通过验证结果位置不是 来检查是否找到了字符串NSNotFound.它可能听起来有点倒退,但逻辑是坚实的(两个否定,可以这么说).

NSRange nameResult  = [actorz.actorNaam rangeOfString:searchText options:NSCaseInsensitiveSearch|NSDiacriticInsensitiveSearch];
NSRange descrResult = [actorz.actorBeschrijving rangeOfString:searchText options:NSCaseInsensitiveSearch|NSDiacriticInsensitiveSearch];

if ( nameResult.location != NSNotFound || descrResult.location != NSNotFound ) {
    [self.filteredListContent addObject:actorz];
}

请注意,此代码段将查找包含搜索字符串的名称,而不仅仅是名称相等.您可能希望使用原始代码更改它.你当然必须删除nameResult,因为它是多余的:

NSComparisonResult result = [actorz.actorNaam compare:searchText options:(NSCaseInsensitiveSearch|NSDiacriticInsensitiveSearch) range:[actorz.actorNaam rangeOfString:searchText options:(NSCaseInsensitiveSearch|NSDiacriticInsensitiveSearch)]];
NSRange descrResult = [actorz.actorBeschrijving rangeOfString:searchText options:NSCaseInsensitiveSearch|NSDiacriticInsensitiveSearch];
    
if ( result == NSOrderedSame || descrResult.location != NSNotFound ) {
    [self.filteredListContent addObject:actorz];
}

但是,有一种更简单的方法.考虑使用谓词:

NSPredicate *actorPred = [NSPredicate predicateWithFormat:@"actorNaam contains[cd] %@ OR actorBeschrijving contains[cd] %@", searchText, searchText];

self.filteredListContent = [arr filteredArrayUsingPredicate:actorPred];