SELECT username, (SELECT follow
FROM follow
WHERE follow_user_id = user_id) AS following
FROM user
WHERE user_id = 1
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我想知道如何检查是否follow(sub-query(select follow ...))返回一个值.如果是,请将其替换为"是".如果没有,则将其替换为"否".
使用案例陈述
select username,
Case When Exists
(select * from follow
where follow_user_id = user_id)
Then 'Yes' Else 'No' End following
from user
where user_id = 1
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