Dav*_*arx 5 python sql database oracle pandas
我正在使用Oracle数据库.我可以这么做:
import pandas as pd
import pandas.io.sql as psql
import cx_Oracle as odb
conn = odb.connect(_user +'/'+ _pass +'@'+ _dbenv)
sqlStr = "SELECT * FROM customers"
df = psql.frame_query(sqlStr, conn)
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但我不知道如何处理绑定变量,如下所示:
sqlStr = """SELECT * FROM customers
WHERE id BETWEEN :v1 AND :v2
"""
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我尝试过这些变化:
params = (1234, 5678)
params2 = {"v1":1234, "v2":5678}
df = psql.frame_query((sqlStr,params), conn)
df = psql.frame_query((sqlStr,params2), conn)
df = psql.frame_query(sqlStr,params, conn)
df = psql.frame_query(sqlStr,params2, conn)
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以下作品:
curs = conn.cursor()
curs.execute(sqlStr, params)
df = pd.DataFrame(curs.fetchall())
df.columns = [rec[0] for rec in curs.description]
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但这个解决方案只是......不太优雅.如果可以的话,我想在不创建游标对象的情况下这样做.有没有办法用大熊猫做整件事?
据我所知,pandas 期望 SQL 字符串在传递之前完全形成。考虑到这一点,我会(并且总是)使用字符串插值:
params = (1234, 5678)
sqlStr = """
SELECT * FROM customers
WHERE id BETWEEN %d AND %d
""" % params
print(sqlStr)
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这使
SELECT * FROM customers
WHERE id BETWEEN 1234 AND 5678
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所以这应该psql.frame_query很好。(根据我使用 postgres、mysql 和 sql server 的经验,确实如此)。