用Ajax响应替换div的内部HTML

Question

我试图在一段时间后改变div的内部HTML.我得到了正确的回应,我想用Ajax.但无法替换后选择的内部HTML和Ajax响应.我的代码有什么问题..

HTML

      <p class="time ui-li-desc" data-time="2013-02-13 11:30:08" >
    51 seconds ago<img alt="image" src="images/read.png"></p>

      <p class="time ui-li-desc" data-time="2013-02-13 11:30:16" >
    58 seconds ago<img alt="image" src="images/read.png"></p>
.
.
.
.
.
      <p class="time ui-li-desc" data-time="2013-02-13 11:40:08" >
    10 minute ago<img alt="image" src="images/read.png"></p>

j查询

setInterval(function() { 
            $( ".time" ).each(function( index ) {
                var sendTime=  $(this).attr("data-time");
                dataString = "sendtime="+sendTime+"&q=convertTime";
                $.ajax({
                    type: "POST",
                    url: "data_handler.php",
                    data: dataString,                   
                    cache: true,
                    success: function(response) {
                        alert(response);
                        $(this).html(response);
                        //alert(response);
                    }
                });
            });
        }, 5000);

Answer 1

this是回调中的窗口.使用给出的值callback:

        $( ".time" ).each(function(index , elem) {
            var sendTime=  $(this).attr("data-time");
            dataString = "sendtime="+sendTime+"&q=convertTime";
            $.ajax({
                type: "POST",
                url: "data_handler.php",
                data: dataString,                   
                cache: true,
                success: function(response) {
                    alert(response);
                    $(elem).html(response);
                }
            });
        });

你并不需要定义一个新的变量,以保护this在jQuery已经为您完成.

Answer 2

由于您将异步函数与回调一起使用，因此this您的回调并非来自同一上下文。您需要保存this在回调中使用的变量。

尝试这样：

setInterval(function() { 
            $( ".time" ).each(function( index ) {
                var sendTime=  $(this).attr("data-time");
                dataString = "sendtime="+sendTime+"&q=convertTime";
                var self = this;
                $.ajax({
                    type: "POST",
                    url: "data_handler.php",
                    data: dataString,                   
                    cache: true,
                    success: function(response) {
                        alert(response);
                        $(self).html(response);
                        //alert(response);
                    }
                });
            });
        }, 5000);