使用SQL CTE表来包含路径和所有子项

Question

我有以下分层树表

GO
DROP TABLE #tbl 
GO
CREATE TABLE #tbl (Id int , ParentId int)
INSERT  INTO #tbl (Id, ParentId) VALUES  (0, NULL)
INSERT  INTO #tbl (Id, ParentId) VALUES  (1, 0)
INSERT  INTO #tbl (Id, ParentId) VALUES  (2, 1)
INSERT  INTO #tbl (Id, ParentId) VALUES  (3, 1)
INSERT  INTO #tbl (Id, ParentId) VALUES  (4, 2)
INSERT  INTO #tbl (Id, ParentId) VALUES  (5, 2)
INSERT  INTO #tbl (Id, ParentId) VALUES  (6, 3)
INSERT  INTO #tbl (Id, ParentId) VALUES  (7, 3)
GO

哪个映射到后面的树

0
+- 1
   +- 2
      +- 4
      +- 5
   +- 3
      +- 6
      +- 7

使用CTE Recursive表,如何获取所选节点的路径以及所有子节点.例如,2作为输入,我如何获得以下数据(如果可能,请订购)

Id, ParentID
-------
 0, NULL 
 1, 0
 2, 1
 4, 2
 5, 2

我知道我可以通过以下语句遍历树(获取路径)

WITH RecursiveTree AS (
    -- Anchor
    SELECT *
        FROM #tbl
        WHERE Id = 2
    UNION ALL
        -- Recursive Member
        SELECT Parent.*
        FROM 
            #tbl AS Parent
            JOIN RecursiveTree AS Child ON Child.ParentId = Parent.Id
)
SELECT * FROM RecursiveTree

并通过以下陈述,在树中遍历(让所有孩子)

WITH RecursiveTree AS (
    -- Anchor
    SELECT *
        FROM #tbl
        WHERE Id = 2
    UNION ALL
        -- Recursive Member
        SELECT Child.*
        FROM 
            #tbl AS Child
            JOIN RecursiveTree AS Parent ON Child.ParentId = Parent.id
)
SELECT * FROM RecursiveTree

问题:如何将这两个命令合并为一个？

Answer 1

只需使用这两个选择的 UNION

SQLFiddle 演示

WITH RecursiveTree AS (
    -- Anchor
    SELECT *
        FROM #tbl
        WHERE Id = 2
    UNION ALL
        -- Recursive Member
        SELECT Parent.*
        FROM 
            #tbl AS Parent
            JOIN RecursiveTree AS Child ON Child.ParentId = Parent.Id
),
RecursiveTree2 AS
(
    -- Anchor
    SELECT *
        FROM #tbl
        WHERE Id = 2
    UNION ALL
        -- Recursive Member
        SELECT Child.*
        FROM 
            #tbl AS Child
            JOIN RecursiveTree2 AS Parent ON Child.ParentId = Parent.id
)
select * from
(
SELECT * FROM RecursiveTree
union
SELECT * FROM RecursiveTree2
) t
order by id