Leo*_*Leo 6 android particle-system libgdx
我用libgdx在我的android设备上画火:
ParticleEffect effect;
ParticleEffectPool fireEffectPool;
Array<PooledEffect> effects = new Array<PooledEffect>();
@Override
public void create()
{
...
effect = new ParticleEffect();
effect.load(Gdx.files.internal("particles/fire01.p"), Gdx.files.internal("image"));
effect.setFlip(true, false);
fireEffectPool = new ParticleEffectPool(effect, 1000, 3000);
PooledEffect myEffect = fireEffectPool.obtain();
myEffect.setPosition(200, 400);
effects.add(myEffect);
...
}
Run Code Online (Sandbox Code Playgroud)
我可以通过编程方式旋转,设置速度或缩放效果吗?
是。查看ParticleEmitterTest:https : //github.com/libgdx/libgdx/blob/master/tests/gdx-tests/src/com/badlogic/gdx/tests/ParticleEmitterTest.java
您只需要获取一个粒子发射器:
emitter = effect.getEmitters().first();
emitter.getScale().setHigh(5, 20);
Run Code Online (Sandbox Code Playgroud)
我通过使用此代码作为基础http://badlogicgames.com/forum/viewtopic.php?f=11&t=7060#p32607找到了粒子效应旋转问题的解决方案
并添加一个小的变化,以保持效果的幅度.希望能帮助到你.
public void rotateBy(float amountInDegrees) {
Array<ParticleEmitter> emitters = particleEffect.getEmitters();
for (int i = 0; i < emitters.size; i++) {
ScaledNumericValue val = emitters.get(i).getAngle();
float amplitude = (val.getHighMax() - val.getHighMin()) / 2f;
float h1 = amountInDegrees + amplitude;
float h2 = amountInDegrees - amplitude;
val.setHigh(h1, h2);
val.setLow(amountInDegrees);
}
}
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
2903 次 |
| 最近记录: |