String.replaceAll()不起作用

Question

我正在编辑一些来自tesseract ocr的电子邮件.

这是我的代码:

 if (email != null) {
        email = email.replaceAll(" ", "");
        email = email.replaceAll("caneer", "career");
        email = email.replaceAll("canaer", "career");
        email = email.replaceAll("canear", "career");
        email = email.replaceAll("caraer", "career");
        email = email.replaceAll("carear", "career");
        email = email.replace("|", "l");
        email = email.replaceAll("}", "j");
        email = email.replaceAll("j3b", "job");
        email = email.replaceAll("gmaii.com", "gmail.com");
        email = email.replaceAll("hotmaii.com", "hotmail.com");
        email = email.replaceAll(".c0m", ".com");
        email = email.replaceAll(".coin", ".com");
        email = email.replaceAll("consuit", "consult");
    }
    return email;

但输出不正确.

输入:

amrut=ac.hrworks@g mai|.com

输出:

lalcl.lhlrlwlolrlklsl@lglmlalil|l.lclolml

但是当我在每次替换后将结果分配给新的String时,它工作正常.为什么在同一个String中连续赋值不起作用？

Answer 1

您将在Javadoc中注意String.replaceAll(),第一个参数是正则表达式.

句点(.)和pipe(|)一样具有特殊含义,就像大括号(})一样.您需要将它们全部转义,例如:

email = email.replaceAll("gmaii\\.com", "gmail.com");

Answer 2

(这是Java吗？)

请注意,在Java中,replaceAll接受正则表达式,并且点匹配任何字符.你需要逃避点或使用

somestring.replaceAll(Pattern.quote("gmail.com"), "replacement");

还要注意这里的拼写错误:

email = emai.replaceAll("canear", "career");

应该

email = email.replaceAll("canear", "career");

Answer 3

你必须逃离.通过\\.类似以下内容:

if (email != null) {
    email = email.replaceAll(" ", "");
    email = email.replaceAll("caneer", "career");
    email = email.replaceAll("canaer", "career");
    email = email.replaceAll("canear", "career");
    email = email.replaceAll("caraer", "career");
    email = email.replaceAll("carear", "career");
    email = email.replace("|", "l");
    email = email.replaceAll("}", "j");
    email = email.replaceAll("j3b", "job");
    email = email.replaceAll("gmaii\\.com", "gmail.com");
    email = email.replaceAll("hotmaii\\.com", "hotmail.com");
    email = email.replaceAll("\\.c0m", "com");
    email = email.replaceAll("\\.coin", "com");
    email = email.replaceAll("consuit", "consult");
}
return email;

Answer 4

通过实现replaceAll()第一个参数,regex你可以使你的比较更少

例如,您可以career通过以下方法检查单词可能的拼写错误regex

email = email.replaceAll("ca[n|r][e|a][e|a]r", "career"));

Answer 5

您正在使用一些正则表达式字符.

请使用\或使用Pattern.quote方法逃避它们

Answer 6

我想你不知道第一个参数replaceAll是正则表达式.

.,|,}可能会从你的期望不同的方式来解释.

.   Any character (may or may not match line terminators)

http://docs.oracle.com/javase/6/docs/api/java/util/regex/Pattern.html

对于空间,你最好使用

\s  A whitespace character: [ \t\n\x0B\f\r]

并以领先的方式逃避其他特殊人物 \\