Alb*_*elB 72 javascript ajax jquery jquery-select2 jquery-select2-3
好吧,我确定这里有一些简单的设置错误,但我不是100%它是什么.
所以我试图使用Select2 AJAX方法作为用户搜索数据库和选择结果的方式.呼叫本身会返回结果,但不允许我从列表中选择答案.它似乎也不允许您在悬停或向上/向下箭头上"选择"它.所以不用多说,这是我的代码:
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.9.0/jquery.min.js"></script>
<link rel="stylesheet" type="text/css" href="select2/select2.css" media="screen" />
<script src="select2/select2.js"></script>
<script src="select.js"></script>
</head>
<body>
<input type="text" style="width: 500px" class="select2">
</body>
</html>
jQuery(function() {
var formatSelection = function(bond) {
console.log(bond)
return bond.name
}
var formatResult = function(bond) {
return '<div class="select2-user-result">' + bond.name + '</div>'
}
var initSelection = function(elem, cb) {
console.log(elem)
return elem
}
$('.select2').select2({
placeholder: "Policy Name",
minimumInputLength: 3,
multiple: false,
quietMillis: 100,
ajax: {
url: "http://localhost:3000/search",
dataType: 'json',
type: 'POST',
data: function(term, page) {
return {
search: term,
page: page || 1
}
},
results: function(bond, page) {
return {results: bond.results, more: (bond.results && bond.results.length == 10 ? true: false)}
}
},
formatResult: formatResult,
formatSelection: formatSelection,
initSelection: initSelection
})
})
{
error: null,
results: [
{
name: 'Some Name',
_id: 'Some Id'
},
{
name: 'Some Name',
_id: 'Some Id'
}
]
}
一切似乎都正确拉入,但我无法真正选择答案并将其输入到框中.我的代码中某处有问题吗？
Alb*_*elB 139
看了另一个答案之后,似乎我还需要在每次调用时传递id字段,否则它将禁用输入.
修复它的示例代码:
$('.select2').select2({
placeholder: "Policy Name",
minimumInputLength: 3,
multiple: false,
quietMillis: 100,
id: function(bond){ return bond._id; },
ajax: {
url: "http://localhost:3000/search",
dataType: 'json',
type: 'POST',
data: function(term, page) {
return {
search: term,
page: page || 1
}
},
results: function(bond, page) {
return {results: bond.results, more: (bond.results && bond.results.length == 10 ? true: false)}
}
},
formatResult: formatResult,
formatSelection: formatSelection,
initSelection: initSelection
})
由于这一点不断上升,我会详细说明一下..select2()方法需要id在所有结果上使用唯一字段.谢天谢地,有一个解决方法.该id选项接受如下函数:
function( <INDIVIDUAL_RESULT> ) {
// Expects you to return a unique identifier.
// Ideally this should be from the results of the $.ajax() call.
}
由于我的唯一标识符<RESULT>._id,我只是return <RESULT>._id;
小智 12
问题是JSON数据需要一个名为"id"的属性.没有必要
id:function(bond){return bond._id; }
如果数据本身没有id,你可以在processResults上添加一个函数, 就像这里一样.
$(YOUR FIELD).select2({
placeholder: "Start typing...",
ajax: {
type: "POST",
contentType: "application/json; charset=utf-8",
url: "YOUR API ENDPOINT",
dataType: 'json',
data:
function (params) {
return JSON.stringify({ username: params.term });
},
processResults: function (data, page) {
var results = [];
$.each(JSON.parse(data.d), function (i, v) {
var o = {};
o.id = v.key;
o.name = v.displayName;
o.value = v.key;
results.push(o);
})
return {
results: results
};
},
cache: true
},
escapeMarkup: function (markup) { return markup;},
minimumInputLength: 1,
templateResult: function (people) {
if (people.loading)
return people.text;
var markup = '<option value="' + people.value + '">' + people.name + '</option>';
return markup;
},
templateSelection: function (people) { return people.value || people.text }
});
就像Dropped.on.Caprica所说：每个结果项都需要一个唯一的ID。
因此，只需为每个结果分配id一个唯一的数字：
$('#searchDriver').select2({
ajax: {
dataType: 'json',
delay: 250,
cache: true,
url: '/users/search',
processResults: function (data, params) {
//data is an array of results
data.forEach(function (d, i) {
//Just assign a unique number or your own unique id
d.id = i; // or e.id = e.userId;
})
return {
results: data
};
},
},
escapeMarkup: function (markup) { return markup; },
minimumInputLength: 1,
templateResult: formatRepo,
templateSelection: formatRepoSelection
});
| 归档时间： |
|
| 查看次数： |
45926 次 |
| 最近记录： |