Moh*_*awi 2 t-sql sql-server loops sum sql-update
UPDATE Houses
SET lStatus = U.codesum
FROM Houses H
JOIN (SELECT ref, SUM(code) AS codesum
FROM Users
GROUP BY ref) AS U ON U.ref = H.ref
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以上代码获取每个房屋的所有用户(Houses表).为所有用户汇总代码列(Users表).最后更新house表的lstatus列中的结果.
我的问题是:我需要重写查询,而不是对代码列求和.相反,我想创建案例陈述.例如:
tempvar = 0 //local variable might be required
For each user {
If code == 1 then tempvar += 5
else if code == 2 then tempvar += 10
etc
tempvar = 0;
}
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一旦我们遍历每个房屋的所有用户,我们现在可以设置lStatus = tempvar.然后应该将tempvar重置为0以用于下一个房屋.
在编写SQL时,应该尽量避免循环和其他过程构造.关系数据库不能轻易地优化这些事物,并且它们通常比它们的声明性对应物慢几个数量级.在这种情况下,SUM(code)用CASE你描述的语句替换你似乎很简单:
UPDATE Houses
SET lStatus = U.codesum
FROM Houses H
JOIN (SELECT ref, SUM(CASE code WHEN 1 THEN 5 WHEN 2 THEN 10 ELSE 0 END) AS codesum
FROM Users
GROUP BY ref) AS U ON U.ref = H.ref
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通过这种方式,SUM仍然可以处理您想象的临时变量将要执行的任务.
此外,如果您有很多案例,您可能会考虑将这些案例放在一个表格中,然后只需加入即可获得总和.这可能更好维护.我在这里使用表变量,但它可能如下所示:
DECLARE @codes TABLE (
code INT NOT NULL PRIMARY KEY,
value INT NOT NULL
)
INSERT INTO @codes SELECT 1, 5
INSERT INTO @codes SELECT 2, 10
UPDATE Houses
SET lStatus = U.codesum
FROM Houses H
JOIN (SELECT a.ref, SUM(b.value) AS codesum
FROM Users a
JOIN @codes b on a.code = b.code -- Here we get the values dynamically
GROUP BY a.ref) AS U ON U.ref = H.ref
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