我正在使用etree通过xml文件进行递归.
import xml.etree.ElementTree as etree
tree = etree.parse('x.xml')
root = tree.getroot()
for child in root[0]:
for child in child.getchildren():
for child in child.getchildren():
for child in child.getchildren():
print(child.attrib)
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在python中避免这些嵌套for循环的惯用方法是什么.
getchildren() ? list of Element instances [#]
Returns all subelements. The elements are returned in document order.
Returns:
A list of subelements.
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我在SO中看到了一些帖子,比如 避免嵌套for循环 但是没有直接转换为我的使用.
谢谢.
如果你想获取n树深处的子级,然后迭代它们,你可以这样做:
def childrenAtLevel(tree, n):
if n == 1:
for child in tree.getchildren():
yield child
else:
for child in tree.getchildren():
for e in childrenAtLevel(child, n-1):
yield e
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然后,要使元素深入四层,您只需说:
for e in childrenAtLevel(root, 4):
# do something with e
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或者,如果您想获取所有叶节点(即本身没有任何子节点的节点),您可以执行以下操作:
def getLeafNodes(tree):
if len(tree) == 0:
yield tree
else:
for child in tree.getchildren():
for leaf in getLeafNodes(child):
yield leaf
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