Gre*_*reg 5 json asp.net-mvc-3 asp.net-mvc-4 kendo-ui kendo-grid
我使用Kendo Grid进行内联编辑.当我单击"更新"按钮时,将使用此签名对我的控制器方法进行POST.控制器操作被命中,因此POST正在运行.
[HttpPost]
public HttpResponseMessage SaveAccountAdmin(string jsonCompanyContacts)
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但是,更新操作中的POST数据永远不会到达 - 它始终为null.
update: {
url: "/Company/SaveAccountAdmin",
contentType: "application/json; charset=utf-8",
type: "POST",
dataType: "json",
data: {
jsonCompanyContacts: "John Doe"
}
},
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这是完整的数据源代码.
var dataSource = new kendo.data.DataSource(
{
batch: false,
pageSize: 10,
transport: {
create: {
url: "/Company/SaveAccountAdmin",
contentType: "application/json; charset=utf-8",
type: "POST",
dataType: "json"
},
read: {
url: "/Company/ReadAccountAdmin"
},
update: {
url: "/Company/SaveAccountAdmin",
contentType: "application/json; charset=utf-8",
type: "POST",
dataType: "json",
data: {
jsonCompanyContacts: "John Doe"
}
},
//destroy: {},
parameterMap: function (data, type) {
return kendo.stringify(data);
}
},
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这也不起作用:
update: {
url: "/Company/SaveAccountAdmin",
contentType: "application/json; charset=utf-8",
type: "POST",
dataType: "json",
//data: { "jsonCompanyContacts": kendo.stringify({ jsonCompanyContacts: "John Doe" }) }
data: { "jsonCompanyContacts": "John Doe" }
},
//destroy: {},
parameterMap: function (data, type) {
return kendo.stringify(data);
}
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但是这个工作 - 为什么?
update: {
url: "/Company/SaveAccountAdmin",
contentType: "application/json; charset=utf-8",
type: "POST",
dataType: "json",
//data: { "jsonCompanyContacts": kendo.stringify({ jsonCompanyContacts: "John Doe" }) }
//data: { "jsonCompanyContacts": "John Doe" }
},
//destroy: {},
parameterMap: function (data, type) {
return kendo.stringify({ "jsonCompanyContacts": "John Doe" });
}
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该值不会作为字符串传递给控制器。尝试使用模型。这可能会有所帮助:MVC3 & JSON.stringify() ModelBinding 返回 null 模型
你真的不想那样做。在一种情况下可能有效,但你是在搬起石头砸自己的脚。
模型
public class CompanyContactModel
{
public string CompanyContacts { get; set; }
}
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控制者签名
public JsonResult SaveAccountAdmin(CompanyContactModel companyContactModel)
...
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更好的
public JsonResult SaveAccountAdmin([DataSourceRequest]DataSourceRequest request, CompanyContactModel companyContactModel)
...
Update and Return and put into List
If error: ModelState.AddModelError(string.Empty, e.Message);
DataSourceResult result = [Your Model List].ToDataSourceResult(request, ModelState);
return Json(result, JsonRequestBehavior.AllowGet);
}
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